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borishaifa [10]
3 years ago
14

I need help you guys!!!

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

x_>-4

Step-by-step explanation:

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What is the range of g(x) = - 2x + 3, if the domain is {-2, - 1,0, 1, 2}?
pshichka [43]

Answer:

{ - 1, 1, 7, 23 }

Step-by-step explanation:

To find the range substitute the values from the domain into g(x)

g(-2) = -2(- 2) + 3 = 4 + 3 = 7

g(- 10) = - 2(- 10) + 3 = 20 + 3 = 23

g(1) = - 2(1) + 3 = - 2 + 3 = 1

g(2) = - 2(2) + 3 = - 4 + 3 = - 1

Range is { - 1, 1, 7, 23 }

7 0
3 years ago
An 8-pound bag of tomatoes costs $5.60. At the same rate, what would be the cost of 11 pounds of tomatoes?
Evgesh-ka [11]
Here is the solution to the given problem above.
Given that for an 8 pound bag of tomatoes costs $5.60, we would want to know how much will it be for 11 pounds. First, we should know how much does it cost per pound. So 5.60 divided by 8 is 0.7. So per pound of tomatoes costs $0.7. Now to know how much for 11 pounds, we multiply 0.7 by 11 and we get $7.70. The correct answer therefore would be option C. $7.70. Hope this answer helps.
5 0
3 years ago
Sketch the graph of and identify the axis of symmetry
kaheart [24]
The axis of symmetry is found within the set of parenthesis with the x.  If our h value of the vertex is -4, then the axis of symmetry is x = -4.  D is that choice.  Cannot graph it here, but your vertex is sitting at (-4, 4), it's an upside down parabola, and some other points on this graph are (-5, 0), (-3, 0), (-6, -12), (-2, -12).  You could graph it using those points and the vertex without a problem, I'm sure.
6 0
3 years ago
Read 2 more answers
Evaluate the expression (x^-3y^7/x^3y^6)^0 for x = 11 and y = –7.
Soloha48 [4]
We can simplify it a bit
oh wait,
remember taht x^0=1, no matter what x is

we see the whole thing is to the zero power
the whole thing is equal to 1
doesn't matter what x or y is
the whole thing evaluates to 1
7 0
3 years ago
Need help with solving a 2x2 system of linear equations<br><br> PLEASE HELP ME
Yakvenalex [24]
\bf \begin{array}{llll}&#10;-5x-y=5\\&#10;-5x+y=5\\&#10;-------\\&#10;-10x+0=10&#10;\end{array}\implies -10x=10\implies x=-1

so if x = -1, let's plug that in the second equation

-5(-1)+y = 5
5+y = 5
y = 0
7 0
3 years ago
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