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algol [13]
2 years ago
6

Please help... need help ASAP

Mathematics
1 answer:
abruzzese [7]2 years ago
7 0

Answer:

c

did the test got it right.

Step-by-step explanation:

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Nancy has worn a blue skirt on 8 of the last 20 days.
Gala2k [10]

Answer:

it's just 8/20 so shade 8/20 of the circle

8 0
2 years ago
Read 2 more answers
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
Please help me do this question​
weeeeeb [17]

Answer:

2/10

Step-by-step explanation:

Im pretty sure its 2/10

have a great day:)

6 0
2 years ago
1. Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these
ELEN [110]

Answer:

Ur final grade will go down if you are looking for answers buddy! :)

Step-by-step explanation:

5 0
2 years ago
the brand name of a certain chain of coffee shops has a 53% recognition rate in the town of coffleton. An executive from the com
Degger [83]
This problem can be solve using the Binomial Distribution, it is a recurrence conveyance of the conceivable number of effective results in a given number of trials in each of which there is a similar likelihood of accomplishment.

Let be X: coffleton residents recognize the brand name 

n = 10 

p = 0.53

q = 0.47 

P(X = 4) = 

(10)
 
(4)*(0.53^4)*(0.47^6) = <span>0.00340</span>
7 0
3 years ago
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