1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna11 [10]
3 years ago
11

this morning, jose's car had 16.01 gallons of fuel. now, 1.5 gallons are left. how much fuel did jose use ?

Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

Jose used 14.51 gallons of fuel

You might be interested in
You have 42 coins with a total value of $3.00. Some of the coins are dimes, and the rest are quarters.
nlexa [21]

Answer:

1. $3.00+42=$3.42

2. 4 Dimes , 2 Pennies

Step-by-step explanation:

2. 4 Dimes = 40 cents , 2 pennies = 2 cents

1. Add up 3.00+42 and that is how you could get the answer for number 1 .

6 0
3 years ago
The diameter of a sphere is 12 inches.what is the volume of the sphere to the nearest cubic inch ?
miss Akunina [59]

Answer:

The volume of the sphere is 288π or 904.778 cubic inches.

Step-by-step explanation:

given \\ diameter \: of \: sphere \:  = 12 \: inches \\ radius \: of \: sphere \:  =  \frac{diameter}{2}  \\ radius \:  =  \frac{12}{2}  = 6 \: inches \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {r}^{3}  \\ here \: r \:  =  \: 6 \: in \\ volume \: of \: sphere = \frac{4}{3} \pi  \:  {6}^{3}  \\ \\ volume \: of \: sphere = \frac{4}{3} \pi  \times 216 \\  \:  \:  = 4\pi \times 72 \\  \:  \:  = 288\pi \\  \:  \:  = 904.778 \: cubic \: inches

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

4 0
3 years ago
This is Algebra btw.
Brums [2.3K]
<h2>Step-by-step explanation:</h2>

Given equations;

y₁ = 3x - 8               -------------------(i)

y₂ = 0.5x + 7          --------------------(ii)

To fill the table, substitute the values of x into equations (i) and (ii)

=> At x = 0

y₁ = 3(0) - 8 = -8

y₂ = 0.5(0) + 7 = 7

=> At x = 1

y₁ = 3(1) - 8 = -5

y₂ = 0.5(1) + 7 = 7.5

=> At x = 2

y₁ = 3(2) - 8 = -2

y₂ = 0.5(2) + 7 = 8

=> At x = 3

y₁ = 3(3) - 8 = 1

y₂ = 0.5(3) + 7 = 8.5

=> At x = 4

y₁ = 3(4) - 8 = 4

y₂ = 0.5(4) + 7 = 9

=> At x = 5

y₁ = 3(5) - 8 = 7

y₂ = 0.5(5) + 7 = 9.5

=> At x = 6

y₁ = 3(6) - 8 = 10

y₂ = 0.5(6) + 7 = 10

=> At x = 7

y₁ = 3(7) - 8 = 13

y₂ = 0.5(7) + 7 = 10.5

=> At x = 8

y₁ = 3(8) - 8 = 16

y₂ = 0.5(8) + 7 = 11

=> At x = 9

y₁ = 3(9) - 8 = 19

y₂ = 0.5(9) + 7 = 11.5

=> At x = 10

y₁ = 3(10) - 8 = 22

y₂ = 0.5(10) + 7 = 12

The complete table is attached to this response.

(ii) To find the solution of the system of equations using the table, we find the value of x for which y₁ and y₂ are the same.

As shown in the table, that value of <em>x = 6</em>. At this value of x, the values of y₁ and y₂ are both 10.

5 0
3 years ago
Help ( correct answer ) 16÷(4)(2)-3(2)÷2+1
Bess [88]
16 ÷ (4)(2) - 3(2) <span>÷ 2+1
16 </span>÷ 8 - 6 <span>÷ 3
2 - 2
0

Answer: 0</span>
3 0
3 years ago
Read 2 more answers
A ​$310 suit is marked down by 20​%. Find the sale price.
loris [4]

Answer:

the answer is 62!

Step-by-step explanation:

multiply

5 0
3 years ago
Read 2 more answers
Other questions:
  • Solve the boundary value problem
    9·1 answer
  • The -30 is the one I need help on
    12·1 answer
  • In a quadrilateral, consecutive angles and opposite angles are congruent. What is the most specific name of the figure?
    14·1 answer
  • Explain why 3(x+4)=3(x-5) has no solution. Choose the best response below.
    5·2 answers
  • Anyone want 2 trade brainliests with me or trade 50 points for a brainlist?
    12·2 answers
  • Find the value of x.
    5·1 answer
  • I need help my ASAP:):);)
    15·2 answers
  • 3(-4b+1) = 15<br> pls help asap
    15·1 answer
  • Help please, I don’t understand this question.
    6·1 answer
  • I need the answers to these problems for my test corrections.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!