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abruzzese [7]
3 years ago
15

the height of an object thrown vertically is given by s=-16t^2+100t+200. Height is meter and time is n seconds.

Mathematics
1 answer:
koban [17]3 years ago
5 0

Answer:

456.25m

Step-by-step explanation:

Since the question did not ask for what to find, we can as well look for the maximum height reached by the object

Given the height of an object thrown vertically expressed as;

s=-16t^2+100t+200.

At max height,

dS/dt = 0

-32t+100 = 0

-32t = -100

t = 100/32

t = 3.125s

Get the Max height

s(3.125) = -16(3.125)²+100(3.125)+200

s(3.125) = -156.25+312.5+200

s(3.125) = 456.25m

Hence the maximum height reached by the object is 456.25m

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A set can be represented by its elements or the properties that each of its members must meet can be described using set-builder notation.

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