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JulsSmile [24]
3 years ago
14

I don't want a simple answer. I want to know how to do it.

Mathematics
1 answer:
puteri [66]3 years ago
4 0
The image is a bit hard to make out, so I'm going to make some guesses. It looks like it says PN=12, QP=8, and PM=17, and you're asked to find QR.

You know that \Delta NPM and \Delta NQR are similar, which means their corresponding sides are proportional in length. So there's some constant c such that

NP=cNQ
PM=cQR
MN=cRN

To find QR, you need to know PM and the constant c.

Clearly, NQ=NP+PQ=12+8=20. So, the first equation becomes

NP=cNQ\iff12=20c\implies c=\dfrac{12}{20}=\dfrac35

Then in the second equation, you have

17=\dfrac35QR\implies QR=17\times\dfrac53=\dfrac{85}3=28.\overline3
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Step-by-step explanation:

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Find the area of the regular polygon​
Y_Kistochka [10]

Answer:

A = 374.123 ft^2

Step-by-step explanation:

First, lets calculate the perimeter:

Perimeter (p) = side length (s) * number of sides (n)

p = s * n

p = 12 * 6

p = 72

Next, lets find the apothem, which is the shortest length from any side to the middle. It's like the radius in a circle, but more complicated.

Apothem (a) = side length (s) / ( 2 * tan(180/number of sides (n)) )

a = \frac{s}{2 * tan (\frac{180}{n} )}

a = \frac{12}{2 * tan (\frac{180}{6} )}

a = \frac{12}{2 * \frac{\sqrt{3} }{3}}

a = \frac{12}{\frac{2\sqrt{3} }{3}}

a = \frac{12*3}{2\sqrt{3}}

a = \frac{6*3}{\sqrt{3}}

a = \frac{18}{\sqrt{3}}

Now, finally, to find the area of a regular polygon, we use the following equation:

Area (A) = ( apothem (a) * perimeter (p) ) / 2

A = \frac{a * p}{2}

A = \frac{\frac{18}{\sqrt{3} }  * 72}{2}

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A = \frac{640}{\sqrt{3}}

Turning into a decimal:

A = 374.123 ft ^2

8 0
2 years ago
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