s = hours it takes the small pipe on its own.
L = hours it takes the large pipe on its own.
we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?
well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.
we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.
in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.
and you can round that up as needed.
9m+5=-13
9m=-18
m=-18/9
m=-2
Answer:
(11-h)^2+ (0-k)^2=121
Step-by-step explanation:
(x−h)^2+(y−k^)2=r^2. this is formula for standard form I think
plug in :)
(11-h)^2+ (0-k)^2=11^2(equals 121)
the distance of the circle is 22 because if you sketch this out, the distance between the two endpoints is 22 if you count it out.This means the radius is 11 since diameter is 22
sorry if this is wrong but hope it helps
The answer is s=(1/3) t=-1 r=3