Let f(x)=ex.

HELPPPPPPPPPP PLEASE

777dan777 [17]

Answer:

P = (nRT)/V

Step-by-step explanation:

Step 1: Write formula

PV = nRT

Step 2: Divide both sides by V

P = (nRT)/V

5 0

4 years ago

What shape would the cross section perpendicular to the base be? Why? A square B triangle C rectangle D trapezoid

erik [133]

Answer:

Step-by-step explanation:

Retangle

Thanks hope this helped

4 0

3 years ago

The note A has a frequency of 880 hertz. The note D has a frequency of 1,175 hertz. Find the ratio of D to A to two decimal plac

Trava [24]

Step-by-step explanation:

We have,

The frequency of note A is 880 Hz and the frequency of note D is 1175 Hz. It is required to find the ratio of D to A.

It means $\dfrac{f_D}{f_A}$ .

Using the values of frequency of D and A. So,

$\dfrac{f_D}{f_A}=\dfrac{1175}{880}$

In decimal form,

$\dfrac{f_D}{f_A}=1.33$

In integer form,

$\dfrac{f_D}{f_A}=\dfrac{1175 }{880}\\\\\dfrac{f_D}{f_A}=\dfrac{235}{176}$

5 0

4 years ago

Read 2 more answers

Jorgen made deposits of $250 at the end of each year for 12 years. The rate received was 6% annually. What's the value of the in

svet-max [94.6K]

FV = P( $\frac{ (1+r)^{n}-1 }{r}$ )

Where, FV = Value after 12 years, P= Yearly deposits = $250, r= Rate = 6% = 0.06, n=Number of years = 12 years.

Then,
FV= 250 ( $\frac{( 1+0.06)^{12} -1 }{0.06}$ ) = $4,217.50

8 0

4 years ago

Read 2 more answers

Integrating sums of functions

Andrei [34K]

Answer:

(a) -12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Calculus

Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Swapping Limits]: $\displaystyle \int\limits^b_a {f(x)} \, dx = -\int\limits^a_b {f(x)} \, dx$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Integration Property [Splitting Integral]: $\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int\limits^6_4 {f(x)} \, dx = 5$

$\displaystyle \int\limits^4_{10} {f(x)} \, dx = 8$

$\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx$

Step 2: Solve Pt. 1

[Integral] Rewrite [Integration Property - Addition]: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = \int\limits^{10}_6 {4f(x)} \, dx + \int\limits^{10}_6 {10} \, dx$
[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4\int\limits^{10}_6 {f(x)} \, dx + 10\int\limits^{10}_6 {} \, dx$

Step 3: Redefine

Manipulate the given integral values.

[Integrals] Combine [Integration Property - Splitting Integral]: $\displaystyle \int\limits^6_4 {f(x)} \, dx + \int\limits^4_{10} {f(x)} \, dx = \int\limits^6_{10} {f(x)} \, dx$
[Integral] Rewrite: $\displaystyle \int\limits^6_{10} {f(x)} \, dx = \int\limits^6_4 {f(x)} \, dx + \int\limits^4_{10} {f(x)} \, dx$
[Integral] Substitute in integrals: $\displaystyle \int\limits^6_{10} {f(x)} \, dx = 5 + 8$
[Integral] Add: $\displaystyle \int\limits^6_{10} {f(x)} \, dx = 13$
[Integral] Rewrite [Integration Property - Swapping Limits]: $\displaystyle -\int\limits^{10}_6 {f(x)} \, dx = 13$
[Integral] [Division Property of Equality] Isolate integral: $\displaystyle \int\limits^{10}_6 {f(x)} \, dx = -13$

Step 4: Solve Pt. 2

[Integral] Substitute in integral: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10\int\limits^{10}_6 {} \, dx$
[Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10(x) \bigg| \limits^{10}_6$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10(10 - 6)$
[Integral] (Parenthesis) Subtract: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10(4)$
[Integral] Multiply: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = -52 + 40$
[Integral] Add: $\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = -12$

Topic: AP Calculus AB/BC

Unit: Integration

Book: College Calculus 10e

8 0

3 years ago