The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
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Answer:
<h2>
</h2>
Step-by-step explanation:
Steps:
Subtract 4 from both sides:
Simplify:
Divide both sides by 12:
Simplify:
Answer:
x - 7/9 = f(x)^-1
Step-by-step explanation:
f(x) = 9x + 7
y - 7 = 9x
y - 7/9 = 9x/9
Interchange!
x - 7/9 = y
24/.30 is how you would get your answer and 80
Answer:
A: 12/7
Step-by-step explanation:
