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lina2011 [118]
3 years ago
9

PLEASE HELP ME NO LINKS I AM BEGGING U !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

9514 1404 393

Answer:

  x = 70

Step-by-step explanation:

The measure of the angle x° is half the sum of the intercepted arcs.

  x° = (112° +28°)/2 = 140°/2

  x° = 70°

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The scores on a math test are normally distributed with a mean of 78 and a standard deviation of 6. The test scores range from 0
Hunter-Best [27]

Answer:

The estimate for the number of students who took the test is 23.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 78

Standard deviation = 6

Since the normal distribution is symmetric, 50% of the students had scores above the mean and 50% had scores below the mean.

Proportion of students who scored between 72 and 90:

72 = 78 - 6

So 72 is one standard deviation below the mean.

Of the 50% of the students who scored below the mean, 68% scored above 72.

90 = 78 + 2*6

So 90 is two standard deviations above the mean.

Of the 50% of the students who scored above the mean, 95% scored below 72.

Then

0.68*0.5 + 0.95*0.5 = 0.815

81.5% of the students scored between 72 and 90.

Nineteen students had test scores between 72 and 90. Estimate the number of students who took the test.

19 is 91.5% = 0.815 of the total number of students.

How much is 100% = 1?

19 - 0.815

x - 1

0.815x = 19

x = \frac{19}{0.815}

x = 23.3

Rounding to the nearest whole number

The estimate for the number of students who took the test is 23.

6 0
4 years ago
The standard deviation of the sample data 13, 14, 17, and 20 equals if you know that the mean
Dmitry_Shevchenko [17]

Answer:

a) 3.16

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<em>Given sample size 'n' =4</em>

mean of x⁻ = ∑x / n

                  = \frac{13+14+17+20}{4} = \frac{64}{4} =16

          x⁻ = 16

Given data

x              13            14            17         20

x - x⁻         -3           -2              1           4

(x-x⁻)²        9              4              1          16

         ∑(x-x⁻)² = 9 + 4 + 1 +16 =30

The sample Variance

S² = ∑(x-x⁻)²/n-1

S^{2} = \frac{30}{4-1} = \frac{30}{3} =10

<em>The standard deviation of the sample </em>

<em>  S = √10 = 3.1622 ≅3.16</em>

8 0
3 years ago
I bought a pear of pants that were $65 they had 25% off
CaHeK987 [17]
How much you need pay?
65x(1-25%)
=65x75%
=65x0.75
=48.75
Your answer should be $48.75.
8 0
4 years ago
Read 2 more answers
How do you solve this problem? 12^2-4(6)+1÷11^
Delvig [45]
&right now I have 120.090901
6 0
3 years ago
The mass of Earth's moon is about 7 x 10 to the 22 power kilograms. The mass of Jupiter is about 1.89 x 10 to the 27 power kilog
Naya [18.7K]

Answer:

The mass of Jupiter is about 27,000 times the mass of Earth's moon

Step-by-step explanation:

Let

x -----> the mass of Earth's moon

y ----> the mass of Jupiter

we have

x=7*10^{22}\ kg

y=1.89*10^{27}\ kg

we know that

To know how many times the mass of Jupiter is approximately the mass of the earth's moon, divide the the mass of Jupiter by the mass of the earth's moon

\frac{y}{x}

so

\frac{1.89*10^{27}}{7*10^{22}}=\frac{1.89}{7}(\frac{10^{27}}{10^{22}})=0.27(10^{27-22})=0.27(10^{5})=27,000\ times

therefore

The mass of Jupiter is about 27,000 times the mass of Earth's moon

6 0
3 years ago
Read 2 more answers
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