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lina2011 [118]
3 years ago
9

PLEASE HELP ME NO LINKS I AM BEGGING U !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

9514 1404 393

Answer:

  x = 70

Step-by-step explanation:

The measure of the angle x° is half the sum of the intercepted arcs.

  x° = (112° +28°)/2 = 140°/2

  x° = 70°

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Given a mean of 150 and a standard deviation of 25:
pishuonlain [190]
We have to define an interval about the mean that contains 75% of the values. This means half of the values will lie above the mean and half of the values lie below the mean.

So, 37.5% of the values will lie above the mean and 37.5% of the values lie below the mean.

In a Z-table, mean is located at the center of the data. So the position of the mean is at 50% of the data. So the position of point 37.5% above the mean will be located at 50 + 37.5 = 87.5% of the overall data

Similarly position of the point 37.5% below the mean will be located at 
50 - 37.5% = 12.5% of the overall data

From the z table, we can find the z value for both these points. 12.5% converted to z score is -1.15 and 87.5% converted to z score is 1.15.

Using these z scores, we can find the values which contain 75% of the values about the mean.

z score of -1.15 means 1.15 standard deviations below the mean. So this value comes out to be:

150 - 1.15(25) = 121.25

z score of 1.15 means 1.15 standard deviations above the mean. So this value comes out to be:

150 + 1.15(25) = 178.75

So, the interval from 121.25 to 178.75 contains the 75% of the data values. 
4 0
3 years ago
What precentage of total hours (50) was spent playing soccor (5)
hammer [34]
If the numbers are the percentage then the answer would be 10
4 0
3 years ago
What is the area of this figure? Enter your answer as a decimal in the box. cm² A parallelogram with a length of 11 cm. A triang
Art [367]
Given:
Parallelogram length = 11 cm
triangle atop the parallelogram : short leg = 7 cm
Right triangle inside the parallelogram : long leg = 9cm

Area of parallelogram = base * height
A = 11cm * 9cm
A = 99 cm²

Area of a triangle atop the parallelogram:
A = ab/2
A = (11cm * 7cm)/2
A = 77 cm² / 2
A = 38.5 cm²

Total area of the figure
99 cm² + 38.5 cm² = 137.5 cm²
3 0
3 years ago
Read 2 more answers
Find a number in the sequence<br><br> 1) 100, 400, 610, ?, 652<br><br> 2) 342, 128, ?, 26
dsp73

Answer:

1.  460

2.  216

Step-by-step explanation:

1.

From the series ,

100 , 400 , 610 , ? , 652

Writing the the digits in the revere order , i.e

001 , 004 , 016 , ? , 256

Now,

Now , getting the number in the form of the multiple of 4 as -

1  ,   1 * 4 = 4  ,   4 * 4 = 16 ,  ?  , 64 * 4 = 4  

Hence , the value for ?  =  16 * 4 =  64 .

Again , reversing 64 to get the missing number of the series -

460 .

Hence ,

The value for ? is 460 .

2.

From the series ,

342 , 128 , ? , 26

Now, multiplying the first digit with the second digit and merging it to the product of the second and third digit -

3 * 4 and  4 * 2 , 1 * 2 and 2 * 8 , ?

128 , 216 , ?

Hence ,

The value for question mark = 1 * 2 and  1 * 6 = 216

Hence ,

The value for ? is 216 .

4 0
3 years ago
The 7th grade class experienced a 15% decrease in enrollment. Last year, the 7th grade class had 280 students. How many students
Monica [59]

238 students are enrolled in the 7th grade class this year

<u>Solution:  </u>

Given that

Percentage decrease in number of students enrolled in 7th grade = 15%

Number of students enrolled last year = 280  

Need to determine number of students enrolled in 7th grade this year.

Lets assume number of students enrolled this year = x  

<em>Percentage decrease in enrollment </em>= (Number of student enrolled last year – Number of students enrolled this year) whole divided by number of students enrolled last year multiplied by 100

\begin{array}{l}{\Rightarrow 15=\frac{280-x}{280} \times 100} \\\\ {=>15 \times 280=28000-100 x} \\\\ {=>100 \mathrm{x}=28000-4200=23800} \\\\ {\Rightarrow x=\frac{23800}{100}} \\\\ {\Rightarrow x=238}\end{array}

Hence number of students enrolled this year = 238.

7 0
4 years ago
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