Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean mean test score of students.
Number of sample, n = 25
Mean, u = 81.5
Standard deviation, s = 10.2
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z score ×standard deviation/√n
It becomes
81.5 ± 1.96 × 10.2/√25
= 81.5 ± 1.96/× 2.04
= 81.5 ± 3.9984
The lower end of the confidence interval is 81.5 - 3.9984 =77.5
The upper end of the confidence interval is 81.5 + 3.9984 = 85.5
Therefore, with 95% confidence interval, the mean test score of students is between 77.5 and 85.5
You do the same as if it was positive you will multiply -4*-4 to get 16 and then you will multiply 16*-4 to get -64
Hope this helps
y = m
x + b
.
y = 6
x − 7
Hope this helped!
Answer:
4
Step-by-step explanation:
There are 2 outcomes for the first flip and 2 outcomes for the second flip
Multiply
2*2 = 4
Answer:
i really dont know what you are saying, but thanks for the points and have a nice day! always smile peeps!
