Option B is correct.
Step-by-step explanation:
We need to solve: ![\sqrt[3]{x^2}\sqrt[4]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D)
We know that: ![\sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%5Csqrt%5Bb%5D%7Bx%7D%20%3D%5Csqrt%5Bn%2Ab%5D%7Bx.x%7D%3D%20%5Csqrt%5Bn%2Ab%5D%7Bx%5E2%7D)
Applying the above rule:
![\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D%5C%5C%3D%5Csqrt%5B3%2A4%5D%7Bx%5E2.x%5E3%7D%5C%5C%3D%5Csqrt%5B12%5D%7Bx%5E5%7D)
So, Option B is correct.
Keywords: Solving with Exponents
Learn more about Solving with Exponents at:
#learnwithBrainly
Answer:
Step-by-step explanation:
While working at his neighborhood math tutoring center researching the comprehension level of the students Dion investigated that the distribution of the student test scores are normally distributed with a mean of 79.13 and a standard deviation of 6.34. What is the probability that the student scores less than 60.11
We solve using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
z = 60.11 - 79.13/6.34
Given :difference between 2 whole number = 66ratio of the 2 whole number =2:5Let:1 whole number be 2x2 whole number be 5xA/Q
difference between 2 whole number = 66
Let's turn it into algebraic equation:
5x - 2x = 663x= 66x =66 /3x =22
Now Let's put value of x to find two whole numbers
Finaly :1 whole number = 2x1 whole number = 2×221 whole number =44
2 whole number = 5x2 whole number = 5×222 whole number = 110
Standard equation: (x-h)^2 + (y-k)^2 = r^2
Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10
Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2
