The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
</span>
So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
</span>
<span>=====================================================
</span>
<span>Another solution:
</span>
<span>If ann seated in one of the ends, the number of ways = 3*2
</span>
<span>If ann didn't seat in one of the ends , the number of ways = 2*3
</span>
So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
</span></span>
The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
60×4=240
so 240/1 and 60×4
-------
1
both are equal to 240
Answer:
I think it is 60x I may be wrong
Step-by-step explanation:
Just followed order of operations then did the math.
