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shusha [124]
3 years ago
7

Which of the following ordered pairs is a solution of the given system of linear equations?

Mathematics
1 answer:
murzikaleks [220]3 years ago
3 0
Its bbbbbbbbbbbbbbbbbbbbbbbb
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Please help!!!!<br> I desperately need the correct answer I’ve been trying all day!
zysi [14]

Answer:14708

Step-by-step explanation:Exponential Functions:

y=abxy=ab^x this is not right      not correct

y=ab

x

a=starting value = 13000a=\text{starting value = }13000

a=starting value = 13000

r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025

r=rate = 2.5%=0.025

Exponential Growth:\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025

b=1+r=1+0.025=1.025

Write Exponential Function:

y=13000(1.025)xy=13000(1.025)^x

y=13000(1.025)

x

Put it all together

Plug in time for x:\text{Plug in time for x:}

Plug in time for x:

y=13000(1.025)5y=13000(1.025)^{5}

y=13000(1.025)

5

y=14708.30677y= 14708.30677

y=14708.30677

Evaluate

y≈14708y\approx 14708

y≈14708

5 0
3 years ago
Read 2 more answers
If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how
Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0
3 years ago
In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.
alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

6 0
2 years ago
Read 2 more answers
What is the equation of the line with m = 3 and b = 8.25?
quester [9]
Y=3x + 8.25
...................
6 0
3 years ago
6.2megagrams/hectoliter to kilograms/deciliter
lesya [120]

Answer:

6.2 kilograms/ deciliters

Step-by-step explanation:

megagrams to kilograms

1 megagram = 1000 kilograms

hectoliter to deciliter

1 hectoliter = 1000 deciliter

Using conversion factors

6.2megagrams      1000 kilgrams         1 hectoliter

---------------------- * ----------------------- * -------------------------

hectoliter                  1 megagram       1000 deciliters

Canceling like terms

6.2 kilograms/ deciliters

6 0
3 years ago
Read 2 more answers
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