We see nothing below that makes the situation clear for us.
We have no way to know what the angles 'x' and 'y' are, or
even whether they're on the same planet as the circle.
Step-by-step explanation:
look at the graph and translate. and the answer is D
Answer:
4 1/2 hours
Step-by-step explanation:
Total time worked was ...
2 3/4 + 1 3/4 = (2 +1) + (3/4 +3/4)
= 3 + (1 1/2) = 4 1/2 . . . hours
Answer:
CR = 17 ; PR = 30
Step-by-step explanation:
From the problem hypothesis we know that CD⊥PR or CQ⊥PR(perpendicular) and ∡PCQ ≡∡RCQ (bisector)
so ∡PCQ≡∡RCQ
[CQ]≡[CQ] (common side)
CQ⊥PR
--------------------------------------------
⇒(cathetus - angle case of congruence)⇒ ΔPQC≡ΔRQC so [PQ]≡[QR] (=15) // PR = PQ+QR ⇒ PR=30
from this congruence ⇒ΔPRC = isosceles so PC=CR=17
Hint: in any triangle is bisector of an angle it is perpendicular on the opposite side then triangle is isosceles.
Answer:
- parent: y = x²
- transformed: y = -3x² +4
Step-by-step explanation:
You have correctly recognized that the function is quadratic, so has parent function y = x².
__
You may notice that the function drops by 3 units when x increases or decreases by 1 unit from the vertex. That factor (-3) is the vertical scale factor in the transformed function ...
f(x) = a(x -h)² +k
where "a" is the vertical scale factor and (h, k) is the location of the vertex of the transformed function.
We note that the graphed function has its vertex at (h, k) = (0, 4), so the complete transformed function with a=-3, h=0, k=4 is ...
f(x) = -3x² +4
