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Irina18 [472]
3 years ago
5

2. A certain recessive, lethal gene is carried on the X chromosome. (Lethal genes are those that result in death.) A man marries

a woman who is hybrid for this gene. What sex ratio would be expected among the living children of this couple?
%Male
%Female​
Please help me im stuck!
Biology
1 answer:
son4ous [18]3 years ago
8 0
The surviving children would be 66.7% female and 33.3% male. Of the female children, 50% would be expected to be carriers of this gene (like their mother)
| Xg | X
—————-
X | XXg | XX
—————-
Y | XgY | XY

Pretty ugly, but the best punnet square I can do without a link. The offspring with the “g” are those that carry the lethal gene. The male child that carries it will die, but since it is recessive, the female child will live but will be a carrier for this gene. I hope this helps.
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A man heterozygous for blood type A marries a woman heterozygous for blood type B. What could be the possible blood types of the
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Answer:

Heterozygous A: AO (remember, O type blood is a recessive allele. It's masked by A)

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What is the probability that each of the following pairs of parents will produce the given offspring: 1. AABbCc x aabbcc à AaBbC
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Answer:

1) AaBbCc, 50% - 2) AAbbCC, 3,125% - 3) AaBbCc is 12,5%.

Explanation:

<u>1º cross</u>.

Parental)          AABbCC             x               aabbcc

Gametes)   ABC   AbC   ABC    AbC    ABC    AbC    ABC    AbC

                   abc    abc   abc     abc      abc     abc     abc     abc

Punnet Square)   <em>Only filled with the progeny genotype AaBbCc</em>.

             ABC       AbC       ABC       AbC         ABC      AbC         ABC     AbC

abc      AaBbCc     ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc     ---      AaBbCc    ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc     ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc     ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc     ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc     ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc     ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

abc      AaBbCc    ---      AaBbCc     ---         AaBbCc     ---        AaBbCc    ---  

   

F1 Genotype)    32/64 AaBbCc

                          32/64  AabbCc (shown as the symbol "---" in the      

                          punnet square)

The probability of producing offspring with genotype AaBbCc is 50%.

---------------------------------------------------------------------

<u>2º cross.</u>

Parental)          AABbCc            x               AaBbCc

Gametes)   ABC   ABc   AbC    Abc    ABC    ABc    AbC    Abc

                     ABC   ABc   AbC     Abc   aBC    aBc     abC    abc

Punnet Square)   Only filled with the progeny genotype AAbbCC.

          ABC    ABc      AbC      Abc     ABC     ABc     AbC       Abc

ABC      ---       ---          ---          ---        ---        ---          ---           ---  

ABc       ---       ---          ---          ---        ---        ---          ---           ---  

AbC       ---      ---    AAbbCC     ---       ---         ---     AAbbCC    ---  

Abc       ---       ---          ---           ---       ---        ---          ---           ---

aBC       ---      ---          ---           ---        ---       ---          ---           ---  

aBc       ---       ---          ---           ---        ---       ---          ---           ---  

abC      ---       ---          ---           ---        ---        ---          ---          ---  

abc       ---       ---          ---           ---        ---        ---          ---          ---

   

F1 Genotype)  2/64 AAbbCC

                       The rest of the progeny have different genotypes that are represented with the symbol "---" in the punnet square.

The probability of producing offspring with genotype AAbbCC is 3,125%.

--------------------------------------------------------------------

<u>3º cross.</u>

Parental)          AaBbCc            x              AaBbCc

Gametes)   ABC   ABc   AbC    Abc    aBC    aBc    abC    abc

                     ABC   ABc   AbC    Abc    aBC    aBc    abC    abc

Punnet Square)   Only filled with the progeny genotype AaBbCc.

          ABC       ABc       AbC       Abc      aBC     aBc       abC       abc

ABC      ---           ---          ---           ---         ---        ---           ---      AaBbCc    

ABc       ---           ---          ---           ---         ---        ---      AaBbCc     ---  

AbC      ---           ---           ---          ---          ---    AaBbCc    ---           ---  

Abc       ---           ---           ---          ---     AaBbCc  ---           ---           ---

aBC       ---           ---           ---     AaBbCc    ---         ---          ---           ---

aBc       ---            ---       AaBbCc   ---          ---        ---           ---          ---  

abC      ---       AaBbCc      ---          ---          ---        ---           ---          ---  

abc   AaBbCc       ---            ---       ---           ---        ---           ---          ---

   

F1 Genotype)  8/64 AaBbCc

                       The rest of the progeny have different genotypes that are represented with the symbol "---" in the punnet square.

The probability of producing offspring with genotype AaBbCc is 12,5%.

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