Which expression is equivalent to 6 + 12x?

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (

True [87]

So it tells us that g(3) = -5 and g'(x) = x^2 + 7.

So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))

now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16

Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84

So we have our linear approximation for the two.

If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35

So just to check our linear approximations use that to find g(2.99) and g(3.01)

g(2.99) = -5.1597
g(3.01) = -4.8397

So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.

5 0

3 years ago

Given the two expressions below: 1) 4x2 − 8x + 9 2) 3x2 + 2y + 6 Is the sum of the two expressions above a polynomial? Why or wh

Mkey [24]

Sum of polynomials are always polynomials.

Note that despite it's name, single constants, monomials, binomials, trinomials, and expressions with more than three terms are all polynomials.
For example,
0, π sqrt(2)x, 4x+2, x^2+3x+4, x^2-x^2, x^5+x/ π -1
are all polynomials.

What makes an expression NOT a polynomial?
Expressions that contain non-integer or negative powers of variables, rational functions, infinite series.
For example,
sqrt(x+1), 1/x+4, 1+x+ x^2/2!+x^3/3!+x^4/4!+...., (5x+3)/(6x+7)
are NOT polynomials.

8 0

3 years ago

What is the inverse of the function f(x) = 2x – 10?

Nadusha1986 [10]

Answer:

f⁻¹(x) = (1/2)x +5

Step-by-step explanation:

In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).

... y = 2x -10

... x = 2y -10 . . . . . . swapped variables

... x +10 = 2y . . . . . add 10

... (1/2)x + 5 = y . . . . divide by 2

... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation

6 0

4 years ago

Graph the line y = -2x - 2

Daniel [21]

Answer:

-2x-2

For a line equation for the form of y = mx +b, the slope is m

m= -2

The function has no undefined points nor domain

constraints. There fore, the domain is

domain: -∞<x<∞

The range of polynomial with odd degrees is all the real numbers

range: -∞<f(x)<∞

Step-by-step explanation:

graph is inserted

8 0

2 years ago

Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (2, -1)

jek_recluse [69]

Answer:

The equation of the line is 2x - 3y = 7 ⇒ answer A

Step-by-step explanation:

* Lets revise the relation between the parallel lines

- If two lines are equal then their slopes are equal

- We can make an equation of a line by using its slope and

a point on the line

- If the slope of the line is m and passing through the point (x1 , y1),

then we can use this form [y - y1]/[x - x1] = m to find the equation

* Lets solve the problem

- The line is parallel to the line 2x - 3y = 5

∴ the slope of the line = the slope of the line 2x - 3y = 5

- Rearrange the terms of the equation to be in the form

y = mx + c to find the slope of it

∵ 2x - 3y = 5 ⇒ subtract 2x from both sides

∴ -3y = 5 - 2x ⇒ divide two sides by -3

∴ y = 5/-3 - 2x/-3 ⇒ y = 2/3 x - 5/3

∴ The slop of the line is 2/3

∵ The line passes through point (2 , -1)

* Lets use the rule to find the equation of the line

∵ y - (-1)/x - 2 = 2/3

∴ y + 1/x - 2 = 2/3 ⇒ by using cross multiplication

∴ 3(y + 1) = 2(x - 2) ⇒ open the brackets

∴ 3y + 3 = 2x - 4 ⇒ put x an d y in one side

∴ 2x - 3y = 3 + 4

∴ 2x - 3y = 7

* The equation of the line is 2x - 3y = 7

8 0

3 years ago