Answer:
four
Step-by-step expif this is worng but i had a similar question and that as the answer
Answer:
a = 2
b = 4
c = 8
Step-by-step explanation:
Remember the relationship:

First, in "a" we have:
a) ![8^{1/3} = \sqrt[3]{8} = 2](https://tex.z-dn.net/?f=8%5E%7B1%2F3%7D%20%20%3D%20%5Csqrt%5B3%5D%7B8%7D%20%20%3D%202)
then in the next ones, we can use the result that we obtained in the part a:
b) 
Now we can do exactly the same in c:
c) where first we need to know that:
2*2*2*2 = 4*4 = 16
then:
2^4 = 16
then:
![\sqrt[4]{16} = 16^{1/4} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%2016%5E%7B1%2F4%7D%20%3D%20%202)
Now let's solve the problem:

Answer:
x^2 - 2xy + y^2.
Step-by-step explanation:
(x - y)^2
= (x - y)(x - y)
= x(x -y) - y(x - y)
= x^2 - xy - xy + y^2
= x^2 - 2xy + y^2.
(0,2), (1,2), (2,3), (1,4), (3,1)
Yes because it is a negative number which, on a number line, is behind 0.