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Yuliya22 [10]
2 years ago
5

10. Find the circumference of the circle. Use 3.14 for pi. Round to the nearest unit.

Mathematics
1 answer:
Jlenok [28]2 years ago
7 0
The answer to the 1st question is..
D. 27 cm

The answer to the 2nd question is..
B. 10, 042. 95

Hope this helps!!
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A high school football quarterback has a lifetime pass completion rate of p = 0.15. A random sample of 15 of his games is select
GarryVolchara [31]

Answer: I think it’s skewed right

Step-by-step explanation:

5 0
3 years ago
In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?  ANS
loris [4]

Answer:

The number of musicians in the school is 3 times the number of athletes

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
A square has a diagonal of length 12. Find the length of each side.
White raven [17]

Answer:

3

Step-by-step explanation:

12÷4=3

Hope this will help you!

7 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
Please help me with this question​
Trava [24]

Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.

<h3>What is the Area of a Sector?</h3>

Area of a sector of a circle = ∅/360 × πr²

<h3>What is the Length of an Arc?</h3>

Length of arc = ∅/360 × 2πr

Given the following:

  • Radius (r) = 9 cm
  • Length of arc = 6π cm
  • Area of sector = kπ cm²

Find ∅ of the sector using the formula for length of acr:

∅/360 × 2πr = 6π

Plug in the value of r

∅/360 × 2π(9) = 6π

∅/360 × 18π = 6π

Divide both sides by 18π

∅/360 = 6π/18π

∅/360 = 1/3

Multiply both sides by 360

∅ = 1/3 × 360

∅ = 120°

Find the area of the sector:

Area = ∅/360 × πr² = 120/360 × π(9²)

Area = 1/3 × π81

Area = 27π

Therefore, the value of k is 27.

Learn more about area of sector on:

brainly.com/question/22972014

4 0
2 years ago
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