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notka56 [123]
3 years ago
6

Find the y-intercept of the parabola y = x2 + 6x. Can somebody help?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0

Given:

The equation of the parabola is:

y=x^2+6x

To find:

The y-intercept of the parabola.

Solution:

We have,

y=x^2+6x

Putting x=0 in the given equation, we get

y=(0)^2+6(0)

y=0+0

y=0

Therefore, the y-intercept of the parabola is 0. It means the y-intercept of the given parabola is at point (0,0).

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What are the x-intercepts of the parabola?
puteri [66]

Answer:

(5,0) & (4,0)

Step-by-step explanation:

The x-intercepts are where the graph touches the x-axis. The parabola clearly touches in the x-axis at points 4 and 5.

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Please help this is due today! geometry
sdas [7]
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Answer is 4 units

Explanation:

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7 0
3 years ago
HELP PLEASE
iragen [17]

Answer:

third number = 4,

equation of y, y = 5x - 11

equation of n, n = 4x

equation of x, n + x + y =19

Step-by-step explanation:

so lets write evertything as a n equation. n + x + y =19. N is the first number, x is the second number, and y is the third number. We will write the equation for y as follows 5x - 11. N will be four times the second number, so 4x. If substitute the values for out equation for x we will find what x equals to. So (4x) + x + (5x - 11) = 19

10x = 30

x = 3.

Then you substiute the answer for x in the equation for y. This will get you 5(3) - 11

15 - 11

4 = third number

4 0
3 years ago
Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de
Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=7\\\\H_a:\mu> 7

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25

The degrees of freedom for this sample size are:

df=n-1=49-1=48

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>5.25)=0.000002

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0
3 years ago
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