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mylen [45]
3 years ago
5

Suppose medical records indicate that the length of newborn babies(in inches) is normally distributed with a mean of 20 and a st

andard deviation of 2.6 find the probability that a given infant is between 14.8 and 25.2 inches long

Mathematics
2 answers:
inna [77]3 years ago
6 0

Answer: 95

Step-by-step explanation:

Hope this helps!

Nadusha1986 [10]3 years ago
4 0

Answer:

P=0.954 or 95.4%

Step-by-step explanation:

Using the formula for the standardized normal distribution to find Z:

Z=\frac{X-\mu}{\sigma}

Where μ is the mean (μ=20) and σ is the standard deviation (σ=2.6).  

Z_{1} =\frac{14.8-20}{2.6}=-2.0

Z_{1} =\frac{25.2-20}{2.6}=2.0

In the table of the normal distribution, we can look for positive values z, and these values are going to represent the area under the curve between z=0 and the values searched. the negatives values are found by symmetry (with the corresponding positive value but remember this area is under the left side of the curve).  To find a value in the table, find the units in the first column and the follow over the same row till you find the decimals required.

P_1=0.4772

P_2=0.4772

P_1 represents the probability of length being between 14.8 and 20 (the mean) and P_2 represents the probability of length being between 20 and 25.2, The requested probability is the sum of these two.

P=P_1+P_2=0.954

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