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Verizon [17]
3 years ago
6

HELP

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer:

equaloty

Step-by-step explanation:

zvg

huu

hjj

hjjk

jjkoii

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Solve 2 cube root 8x+9=5
Alborosie
2 times the cube root of 8x+9=5
divide both sides by 2
cube root of 8x+9=2.5
cube everybody (put to 3rd power)
8x+9=2.5^3
8x+9=15.625
minus 9 both sides
8x=6.625
divie both sides by 8
x=0.828125
7 0
3 years ago
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
Timothy and his brothers are selling lemonade and cookies to raise funds for a camping trip. Paul bought two cups of lemonade an
sasho [114]

Answer:

im try ing to think

Step-by-step explanation:

3 0
3 years ago
2 1/3 plus 1 3/4 plz exlain and answer need to be in fraction form
NARA [144]

Answer:

7/12

Step-by-step explanation:

2 1/3 + 1 3/4

7/3 + 7/4

28-21/12

7/12

:)ur wel

8 0
3 years ago
A map has a scale of 1 cm : 5 km. Determine how far apart two cities are if they are 4 cm apart on the map?
Kay [80]

Answer:

he is right its A

Step-by-step explanation:

5 0
3 years ago
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