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cupoosta [38]
3 years ago
15

Peter has a rectangular garden. The length is 22 feet, and the diagonal measures 28 feet. What is the width of the garden? Round

to the nearest tenth.
Mathematics
1 answer:
Natalija [7]3 years ago
3 0
Make the width x. Divide the garden into two triangles, with the diagonal being 28.

Here you use the Pythagorean theorem where 28^2- 22^2= x^2

You get 300= x^2, and when you square root both sides you get x=17.32

Answer: x=17.32

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7 0
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Answer: 166.67π

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8 0
2 years ago
Forty per cent of all those who applied for the job had experience. If 80 people had
Zielflug [23.3K]

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8 0
2 years ago
The length of a rectangle is 12 cm more than its width. Find the
just olya [345]

Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.

Step-by-step explanation:

  • Step 1: Given that the perimeter = 100 cm, let width be x cm and then length = 12 + x.

Perimeter of a rectangle = 2(length + width)

100 = 2(x + 12 + x)

100 = 4x + 24

4x = 100 - 24 = 76

∴ x = 76/4 = 19 cm

∴ Length = 19 + 12 = 31 cm

5 0
3 years ago
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