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2 years ago

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A plumbers plastic pipe is 4 m long, has an inside diameter of 4.0 cm and an outside diameter of 5.0cm. What is the volume of th

e plastic in the pipe?

1 answer:

SCORPION-xisa [38]2 years ago

5 0

Answer: $V=0.0028278\ m^3$

Step-by-step explanation:

Given

Length of the pipe $l=4\ m$

Inside diameter of the pipe $d_i=4\ cm$

Outside diameter of the pipe $d_o=5\ cm$

Volume of the pipe

$\Rightarrow V=\dfrac{\pi }{4}[d_o^2-d_i^2]\\\\\text{Insert the values}\\\\\Rightarrow V=\dfrac{\pi}{4}[5^2-4^2]\times 10^{-4}\times 4\\\\\Rightarrow V=28.278\times 10^{-4}\ m^3\\\\\Rightarrow V=0.0028278\ m^3$

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Answer:65

Step-by-step explanation:

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2 years ago

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How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

2 years ago

A strand of bacteria has a doubling time of 15 minutes. If the population starts with 10 organisms, how long would it take for t

slamgirl [31]

In 90 minutes the population to grow to 700 organisms.

Given that,

A strand of bacteria has a doubling time of 15 minutes.

If the population starts with 10 organisms.

We have to determine,

How long would it take for the population to grow to 700 organisms?

According to the question,

A strand of bacteria has a doubling time of 15 minutes.

If the population starts with 10 organisms.

In 15 minutes strand of bacteria has a doubling time the population starts with 10 organisms.

$\rm = 10 \times 2 = 20 \ bacteria$

In 15 minutes 20 bacteria for the population to grow.

In 30 minutes strand of bacteria has a doubling time the population starts with 20 organisms.

$\rm = 20 \times 2 = 40 \ bacteria$

In 30 minutes 40 bacteria for the population to grow.

In 45 minutes strand of bacteria has a doubling time the population starts with 40 organisms.

$\rm = 40 \times 2 = 80 \ bacteria$

In 45 minutes 80 bacteria for the population to grow.

In 60 minutes strand of bacteria has a doubling time the population starts with 80 organisms.

$\rm = 80 \times 2 = 160 \ bacteria$

In 60 minutes 160 bacteria for the population to grow.

In 75 minutes strand of bacteria has a doubling time the population starts with 160 organisms.

$\rm = 160 \times 2 = 320 \ bacteria$

In 75 minutes 320 bacteria for the population to grow.

In 90 minutes strand of bacteria has a doubling time the population starts with 320 organisms.

$\rm = 320 \times 2 = 640 \ bacteria$

In 90 minutes 640 bacteria for the population to grow.

In 120 minutes strand of bacteria has a doubling time the population starts with 640 organisms.

$\rm = 640 \times 2 = 1280 \ bacteria$

In 120 minutes 1280 bacteria for the population to grow.

Hence, In 90 minutes the population to grow to 700 organisms.

For more details refer to the link given below.

brainly.com/question/3188472

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2 years ago

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An admiral, captain, and commander, all different, are to be chosen from a group of 10 Starfleet officers. How many different ch

zepelin [54]

Answer:

$10C1 *9C1*8C1 = 10*9*8=720$

Step-by-step explanation:

For this case in order to select the one admiral, captain and commander, all different. We are assuming that the order in the selection no matter, so we can begin selecting an admiral then a captain and then a commander.

So we have 10C1 ways to select one admiral since we want just one

Now we have remaining 9 people and we have 9C1 ways to select a captain since we want a captain different from the admiral selected first

Now we have remaining 8 people and we have 8C1 ways to select a commander since we want a commander different from the captain selected secondly.

The term nCx (combinatory) is defined as:

$nCx = \frac{n!}{x! (n-x)!}$

And by properties $nC1= n$

So then the number of possible way are:

$10C1 *9C1*8C1 = 10*9*8=720$

If we select first the captain then the commander and finally the admiral we have tha same way of select $10*9*8=720$

For all the possible selection orders always we will see that we have 720 to select.

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2 years ago

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How do i factor x^4+6x^2-7 completly?

liq [111]

The factoring can be done similarly to a quadratic equation thanks to x^4 being the square value of x^2.

<span>x^4 + 6x^2 - 7
x^4</span><span> - x^2</span> + 7x^2 - 7
(x^4 - x^2) + (<span>7x^2 - 7)
</span>x^2(x^2 - 1) + 7(<span>x^2 - 1)
</span>(x^2 + 7)(x^2 - 1)
<span>(x^2 + 7)(x - 1)(x + 1)
</span>
Factored completely we get: <span>(x^2 + 7)(x - 1)(x + 1)</span>

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2 years ago

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