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3 years ago

F(x) = 5x^3+ 2x^2 - 90x - 36. finding all zeros by factoring and explaining the steps

Mathematics

1 answer:

ella [17]3 years ago

8 0

Answer:

f(x)=5x^3-2x^2-90x-36=0

=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0

x^2-18=0/5x-2=0

x^2=18=x=9√2

5x-2=0

x=2/5

zeros are 9√2,2/5

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If 3a + 2b = 7 and 2a + 2b = 9 , what is the value of

Simora [160]

Hey there :)

We have two equations:
3a + 2b = 7
2a + 2b = 9

We need to solve simultaneously to find the values of a and b

eq.1 3a + 2b = 7
eq.2 ( 2a + 2b = 9 ) x -1 ) multiply by -1 to cancel 2b

3a + 2b = 7
- 2a - 2b = -9 ( Add both together )
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a = - 2

Substitute the value you found for a in a in order to find b

3( - 2 ) + 2b = 7 2( - 2 ) + 2b = 9
- 6 + 2b = 7 OR - 4 + 2b = 9
2b = 13 2b = 13
b = $\frac{13}{2}$ b = $\frac{13}{2}$

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Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

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Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

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