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rosijanka [135]
3 years ago
11

Write an equation that models the sequence 400, 200, 100, 50, ...

Mathematics
2 answers:
Julli [10]3 years ago
3 0
You're starting at 400. Each time you're cutting in half. 

So the common ratio is 1/2 which means the equation is

\Large y = 400(1/2)^{x-1}

which is in the geometric sequence format. So the answer is choice D
Svetlanka [38]3 years ago
3 0

Answer:

he answer is D.)y = 400(1/2)X-1

Step-by-step explanation:


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0≤h(t)≤144, which means that the height of the object can be between 0 and 144 feet, including those limits.
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Witch best describes a triangle acute obtuse right or equlateral
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6 0
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What expression represents the quotient?
Olenka [21]

Answer:

C

Step-by-step explanation:

Given

\frac{5x^2+8x+7}{4x}

Divide each term on the numerator by 4x

= \frac{5x^2}{4x} + \frac{8x}{4x} + \frac{7}{4x}

= \frac{5x}{4} + 2 + \frac{7}{4x}

8 0
3 years ago
What is the distance between point P (primates) and
faltersainse [42]

Answer:

11 units

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
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