Answer:
Step-by-step explanation:
The set {1,2,3,4,5,6} has a total of 6! permutations
a. Of those 6! permutations, 5!=120 begin with 1. So first 120 numbers would contain 1 as the unit digit.
b. The next 120, including the 124th, would begin with '2'
c. Then of the 5! numbers beginning with 2, there are 4!=24 including the 124th number, which have the second digit =1
d. Of these 4! permutations beginning with 21, there are 3!=6 including the 124th permutation which have third digit 3
e. Among these 3! permutations beginning with 213, there are 2 numbers with the fourth digit =4 (121th & 122th), 2 with fourth digit 5 (numbers 123 & 124) and 2 with fourth digit 6 (numbers 125 and 126).
Lastly, of the 2! permutations beginning with 2135, there is one with 5th digit 4 (number 123) and one with 5 digit 6 (number 124).
∴ The 124th number is 213564
Similarly reversing the above procedure we can determine the position of 321546 to be 267th on the list.
Answer:
62.5%
Step-by-step explanation:
1875 diveded by 3000 = 62.5
96
/ \
8 • 12
/ \ / \
4 • 2 • 4 • 3
/ \ / \
2 2 2 2
96 is 2•2•2•2•2•3 or 2^5•3
Did it the longer way but i hope it helps you out.... Answer: 2/3
Answer/Step-by-step explanation:
Given,
10x - 3y = 3
3x + 10y = 30
Rewrite both equation in slope-intercept form, y = mx + b.
Where, m = slope of the line.
Thus,
✔️10x - 3y = 3
-3y = -10x + 3
y = 10/3x - 1
Slope of this line would be 10/3
✔️3x + 10y = 30
10y = -3x + 30
y = -3/10x + 3
The slope of this line is -³/10.
✔️The two lines are pendivukar to each other because the slope of one is the negative reciprocal of the other.
