Ask question

Ask question

All categories

3 years ago

15

In ΔVWX, x = 9.1 inches, w = 5.4 inches and ∠W=161°. Find all possible values of ∠X, to the nearest 10th of a degree

1 answer:

Ganezh [65]3 years ago

4 0

Answer:

NO POSSIBLE TRIANGLES

Step-by-step explanation:

You might be interested in

Can somebody please help me answer this question

andrey2020 [161]

Answer:

the mean is 9

Step-by-step explanation:

add all the numbers then divide by 6

6 0

3 years ago

Read 2 more answers

I need help with question #2. ASAP. Anything is appreciated:)

DedPeter [7]

Y = 4/5x + 30

4/5 because the slope is 4 up, 5 right. 30 is the y-int

4 0

3 years ago

A rectangle is drawn with perimeter 75 cm. The length is 13 more than the width. What is the length?

RideAnS [48]

The length of the rectangle is 25.25.

8 0

4 years ago

Read 2 more answers

What is m∠V ? Round only your final answer to the nearest tenth. 53.9º 56.1º 61.9º 70.0º The figure shows acute triangle U V W.

IrinaVladis [17]

The correct option is: 53.9°

<em><u>Explanation</u></em>

According to the below diagram, $\triangle UVW$ is acute triangle, in which $\overline{UV}= 7.6 inches, \overline{VW}= 8.6 inches$ and $\overline{WU}=7.4 inches$

If we <u>apply cosine rule</u> here, then we will get.....

$cos(V) = \frac{(UV)^2+(VW)^2 -(WU)^2}{2(UV)(VW)}$

Now, plugging the given values, we will get....

$cos(V)=\frac{(7.6)^2+(8.6)^2-(7.4)^2}{2(7.6)(8.6)}\\ \\ cos(V)= \frac{76.96}{130.72}=0.58873...\\ \\ V= cos^-^1(0.58873...)=53.932.... \approx 53.9 degree$

So, the measure of $\angle V$ is 53.9°

5 0

3 years ago

Help! <br> The slope of the line below is -3.

mylen [45]

Answer:

D. y + 7 = -3(x - 5)

Step-by-step explanation:

Point-slope form: y - y₁ = m(x - x₁)

⇒ y - (-7) = -3(x - 5)

⇒ y + 7 = -3(x - 5)

8 0

3 years ago

Read 2 more answers