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Rom4ik [11]
2 years ago
13

Eric plays basketball and volleyball for a total of 95 minutes every day. He plays basketball for 25 minutes longer than he play

s volleyball. Part A: Write a pair of linear equations to show the relationship between the number of minutes Eric plays basketball (x) and the number of minutes he plays volleyball (y) every day. (5 points) Part B: How much time does Eric spend playing volleyball every day? Show your work. (3 points) Part C: Is it possible for Eric to have spent 35 minutes playing basketball if he plays for a total of exactly 95 minutes and plays basketball for 25 minutes longer than he plays volleyball? Explain your reasoning. (2 points)
Mathematics
1 answer:
dangina [55]2 years ago
5 0

Answer:

A) x = y+25

B) 35 minutes

C) 35 ≠85

Step-by-step explanation:

A)  

As we know

X = number of minutes Eric plays basketball

Y = Number of minutes he plays volleyball  

x+y= 95

x = y+25  

B)  

We will replace  

x=y+25 in the first equation and we will get (y+25) + y =95  

On solving,  

y+25+y =95  

25+2y=95  

2y=95-25  

2y=70  

y = 70/2  

y = 35 minutes  

C) X = 35  

x+y= 95  

35+y =95  

y= 95-35  

y = 60 minutes  

Substituting value of Y as 60 , we get  

x = y+25

35 = 60+25

35 ≠85  

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C.P.=RS 180 S.P. =Rs 200 solve it step by step 'I'll give u brainest'​
lubasha [3.4K]

Answer:

Rs20

Step-by-step explanation:

C.P=Rs180

S.P=Rs200

profit =S.P-C.P

=Rs200-Rs180

=Rs20

7 0
3 years ago
One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.
fredd [130]

Answer:

They would need approximately 20 gallons of paint for the water tower, so yes, 25 gallons would be enough.

Step-by-step explanation:

In order to find out if there is enough paint for the surface area of the sphere, you need to first find the radius of the object so you can determine the measure of the entire surface area.  Since they give us the volume, we can use that to solve for the radius using the volume formula:  V = πr³  or 66840.28 = πr³.  Using inverse operations, you can first multiply both sides of the equation by the reciprocal of 4/3 or 3/4, then divide by π, this gives you 15,965 = r³.  In order to find 'r', take the cube root of both sides:  ∛15965 = ∛r³  or r ≈ 25.

Now that you know radius = 25, you can use the formula for surface area:  SA = 4πr²  or 4π(25)² ≈ 7850 ft².  Since one gallon of paint covers 400 square feet, we can take our total and divide by 400 to find the number of gallons:  7850 ÷ 400 ≈ 19.6.  In total, we would need 19.6 gallons of paint for the water tower, so if there are 25 gallons available, there is enough.


3 0
2 years ago
Simplify by dividing <br> 3/5 ÷ -4/9<br><br> 1. -27/20<br> 2. 27/20<br> 3. -12/45<br> 4. 12/45
kramer

Answer:

The answer to your question is -27/20

Step-by-step explanation:

Divide         3/5  ÷  - 4/9

Process

1.- Just multiply the numerator of the first fraction by the denominator of the second fraction.                                      

                    3 x - 9 = -27

2.- Multiply the denominator of the first fraction by the numerator of the second fraction.

                    5 x 4 = 20

3.- Join both results

                               -27/20

5 0
3 years ago
Please help asap!! Thank you
djyliett [7]

Step-by-step explanation:

Hey, there!!

Let's simply work with it,

60° + 2x° + (2x+12)° = 180° { being a linear pair}.

or, 72° + 4x = 180°

4x = 180° - 70°

x =  \frac{108}{4}

Therefore, the value of x is 27°.

Now,

2x° = (2×27)°= 54°

(2x+12)° = 2×27°+12°= 66°.

(x+2)= 27+ 2= 29°

Now, The left angle is 27°.

Therefore, The answer is option A.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
Please help 40 points
Natasha2012 [34]

Answer:

-2 5/9

Step-by-step explanation:

w + (-x) - 2/3

Let w = -5/9  and x = 4/3

-5/9  - 4/3 - 2/3

Get a common denominator

-5/9  -4/3*3/3  -2/3*3/3

-5/9  -12/9  -6/9

Add

-23/9

Change to a mixed number

-2 5/9

4 0
3 years ago
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