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3 years ago

Find the value of x and the value of y. A.x = 15, y = 10 B.x = 20, y = 50 C.x = 50, y = 10 D.x = 50, y = 20

Mathematics

1 answer:

Llana [10]3 years ago

3 0

Answer:

X = 50

Step-by-step explanation:

(5x - 100) + (x - 20) = 180 (sum of angle on a straight line is = 180)

5x + x -100 -120 = 180

6x - 120 = 180

6x = 180 + 120

6x = 300

x = 300/6

x = 50

For y

3y + y + 140 = 180

4y = 180 -140

4y = 40

y = 40/4

y = 10

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The formula F=9/5C+32 converts temperatures from Celsius C to Fahrenheit F. A. Solve the formula for C b. The boiling point of w

liraira [26]

Answer:

(a) $\therefore C=\frac59(F-32)$

(b)The boiling point of water in Celsius scale is 100°C.

(c)The setting in Celsius scale is 26.7°C.

Step-by-step explanation:

Given that,the formula is

$F=\frac95 C+32$ ......(1)

(a)

Given that,

$F=\frac95 C+32$

$\Rightarrow F-32=\frac95 C+32-32$ [ subtracting 32 from both sides]

$\Rightarrow F-32=\frac95 C$

$\Rightarrow \frac95 C=F-32$

$\Rightarrow C=\frac59(F-32)$ ......(2) [Multiplying $\frac59$ ]

$\therefore C=\frac59(F-32)$

(b)

Given that, the boiling point of water is 212°F.

Putting F=212 in equation (2)

$\therefore C=\frac59(212-32)$

$\Rightarrow C=\frac59\times 180$

$\Rightarrow C=5\times 20$

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The boiling point of water is 100°C.

(c)

Given that, a house thermostat is set at 80 degree.

Putting F=80 in equation (2)

$\therefore C=\frac59(80-32)$

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2 years ago

What is the standard form of the points (-3,4) (2,-6)

Bas_tet [7]

The standard form equation of the line connecting the two points is $2x + y = -2$

Linear equation in a standard form is given as $Ax + By = C$

where,

A, B, and C are constants or numbers

x and y are the variables.

To solve this problem, the following steps would be taken:

Step 1: Find the slope of the line connecting points (-3,4) and (2,-6)

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1}$

where,

$(x_1, y_1) = (-3,4)\\(x_2, y_2) = (2,-6)$

Substitute

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Step 2: Find the y-intercept (b) of the line by substituting $(x, y) = (-3,4)$ and $m = -2$ into $y = mx + b$ (slope-intercept form)

$4 = -2(-3) + b\\4 = 6 + b\\4 - 6 = 6 + b - 6\\-2 = b\\b = -2$

Step 3: Write the equation of the line in slope-intercept form by substituting $m = -2$ and $b = -2$ into $y = mx + b$

$y = -2x + (-2)\\y = -2x - 2$

Step 4: Rewrite the equation in standard form $(Ax + By = C)$

$y = -2x - 2\\$

Add $2x$ to both sides

$2x + y = -2x - 2 + 2x\\2x + y = -2$

The standard form equation of the points (-3,4) and (2,-6) is $2x + y = -2$

Learn more about standard form of two points of a linear equation here:

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mel-nik [20]

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Step-by-step explanation:

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