<h3>Answer:</h3>
x = 3
<h3>Explanation:</h3>
The product of the lengths of segments from the intersection point to the circle is the same for both secants.
... 1×6 = 2×x
... 6/2 = x = 3 . . . . . divide by 2
_____
<em>Comment on secant geometry</em>
Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.
When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.
Answer:
odd: 4/7
not 3: 6/7
4 or 5: 2/7
spinner spun 2: there both 1/7 i think im
only in 7th grade ;-;
Step-by-step explanation: well there are 7 spaces so the probabilty
of it landing on an odd space on the wheel is how many odd numbers there are over 7 . and there is only 1 three so the chance that it will not land on 3 is 6/7. there is a 2/7 chance it will land on 4 or 5. and im not to sure abt the last one but like i said im only in the 7th grade i am taking p classes tho so the rest should be right. :D
Answer:
B
Step-by-step explanation:
+ 6 = x ( subtract 6 from both sides )
= x - 6 ( square both sides )
x = (x - 6)² ← expand using FOIL
x = x² - 12x + 36 ( subtract x from both sides )
0 = x² - 13x + 36 , that is
x² - 13x + 36 = 0 ← in standard form
(x - 4)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 9 = 0 ⇒ x = 9
As a check
Substitute these values into the equation and if both sides are equal then they are the solutions.
x = 4
left side =
+ 6 = 2 + 6 = 8
right side = x = 4
Since 8 ≠ 4 then x = 4 is an extraneous solution
x = 9
left side =
+ 6 = 3 + 6 = 9
right side = x = 9
Thus the solution is x = 9 → B
Answer: brand C
Step-by-step explanation:
i just took the quiz