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2 years ago

11

Is it A. B. C. D. I really need help .

1 answer:

ss7ja [257]2 years ago

5 0

I think the answer you’re looking for is
B. 9
-I hope this helps!

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Solve the system substitution y= 4x + 1 and 3x+2y =13

strojnjashka [21]

Given :

${\qquad \sf \dashrightarrow y= 4x + 1 \: –––– \sf \: (i)}$

${\qquad \sf \dashrightarrow 3x + 2y = 13 \: –––– \sf \: (ii)}$

Now, Substituing the value of y in equation (ii) :

${\qquad \sf \dashrightarrow \: 3x + 2y = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 2(4x + 1) = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 8x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x = 13 - 2 }$

${\qquad \sf \dashrightarrow \: 11x = 11 }$

${\qquad \sf \dashrightarrow \: x = \dfrac{11}{11} }$

${\qquad \sf \dashrightarrow \bf \: x = 1 }$

Now, substituting the value of x in equation (i) :

${\qquad \sf \dashrightarrow y= 4x + 1}$

${\qquad \sf \dashrightarrow y= 4(1) + 1}$

${\qquad \sf \dashrightarrow y= 4 + 1}$

${\qquad \bf \dashrightarrow y= 5}$

8 0

1 year ago

Use a graphing utility to approximate (to two decimal places) any relative

iogann1982 [59]

Answer:

Relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and relative maxima DNE.

Step-by-step explanation:

The given function is f(x) = x (x + 7) ...... (1)

We have to calculate the relative maxima and relative minima at point (x, y).

Rearranging the function given above we get.

$y= x^{2} +7x = (x + \frac{7}{2} )^{2} -\frac{49}{4}$

⇒ $y+ \frac{49}{4} = (x + \frac{7}{2} )^{2}$

Now, this is an equation of parabola having vertex at $(-\frac{7}{2} , -\frac{49}{4} )$ and the axis is parallel to positive Y-axis.

Therefore, the function(1) has a relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and the relative maxima DNE. (Answer)

3 0

3 years ago

-4x^2+20-4 in standard form

oksian1 [2.3K]

The answer should be -4x^2+16

4 0

3 years ago

What is the simplified value of the exponential expression 16 Superscript one-fourth?

pochemuha

<u>Answer: </u>

The value of the exponential expression $16^{\frac{1}{4}}$ is 2

<u>Solution:</u>

16 superscript one-fourth= $16^{\frac{1}{4}}$

As per the problem,

We have to find the value of $16^{\frac{1}{4}}$

16 in terms of 2 can be written as $2\times2\times2\times2$

= $(2 \times 2 \times 2 \times 2)^{\frac{1}{4}}$

= $\left(2^{4}\right)^{\frac{1}{4}}$

As per the exponential rule, $a^{(m)^{n}}=a^{m \times n}$

= $2^{4 \times \frac{1}{4}}$

Here, $4\times\frac{1}{4}=1$

= $2^{1}$

= 2

Hence, the value is 2.

9 0

2 years ago

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Which term refers to a pictorial representation of given set of data involving two variables?

timofeeve [1]

C. formula

I hope this helps, thank you.

6 0

2 years ago

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