I'll go slow:
![2\sqrt 7 - \sqrt{28}](https://tex.z-dn.net/?f=2%5Csqrt%207%20-%20%5Csqrt%7B28%7D)
![=2 \sqrt 7 - \sqrt{4 \cdot 7}](https://tex.z-dn.net/?f=%3D2%20%5Csqrt%207%20-%20%5Csqrt%7B4%20%5Ccdot%207%7D)
![=2 \sqrt 7 - \sqrt{4} \cdot \sqrt{7}](https://tex.z-dn.net/?f=%3D2%20%5Csqrt%207%20-%20%5Csqrt%7B4%7D%20%5Ccdot%20%5Csqrt%7B7%7D)
![=2 \sqrt7 - 2 \sqrt 7](https://tex.z-dn.net/?f=%3D2%20%5Csqrt7%20-%202%20%5Csqrt%207)
![=0](https://tex.z-dn.net/?f=%3D0)
Answer: B rational and equal to 0.
Answer:
A. divide both sides by 3
Step-by-step explanation:
3p < 14
We want to isolate p, so we divide both sides by 3
3p/3 < 14/3
p <14/3
First using the given two points we can find the slope (m) of the line
![Slope = m = \frac{Rise}{Run} \\ \\ m= \frac{4-1}{3-0} \\ \\ m=1](https://tex.z-dn.net/?f=Slope%20%3D%20m%20%3D%20%20%5Cfrac%7BRise%7D%7BRun%7D%20%5C%5C%20%20%5C%5C%20%0Am%3D%20%5Cfrac%7B4-1%7D%7B3-0%7D%20%5C%5C%20%20%5C%5C%20%0Am%3D1%20%20)
Thus the slope of given line is 1.
Using slope and a point (0,1) we can write the equation in point slope form as
y - 1= 1(x-0)
y - 1 = x
The above equation is the point-slope form of the equation.
True
It won’t be a Prefect Triangle but it still is one
(sorry my drawing is bad)
Answer:
B: 22.5 degrees
Step-by-step explanation:
The interior angles of a pentagon add up to 540 degrees
(if you dont believe me you can turn a pentagon into three triangles, 3x180 = 540)
So you have four same angles say measure "x" degrees, and one final one that measures "5x" degrees, so 9x = 540, and x = 60
Unless I read the problem wrong, 60 degrees is the answer which is not an option :P
Edit: Yea I read it wrong, the final angle is 5 times the other four angles COMBINED, so that angle measures "20x" degrees.
The total would be 24x = 540, and so x = 22.5