Lol yes I can factor that.
But, this can be factored further.
Answer:
Option D is correct ...
Step-by-step explanation:
because f(x) is defined on x<0 which is only possible in log(-x)
I see. Imagine you have f(x)=|x|. It's a V shaped graph.
Now if f(x)=|x|, 2f(x)=2|x|.
Graph Transformation Rule:
af(x), multiply y-coordinates by a.
*Ultimately, you'd still have a V shaped graph in 2f(x)=2|x|, but the y values of all the coordinates in f(x)=|x| would have to be multiplied by 2 giving you 2f(x)=2|x|.
<h3>Isolate y on both equations then equate </h3>
- x²-3x+2y=-4
- 2y=-x²+3x-4
- y=-x²/2+3/2x-2
Now you can equate it with second one to get x
