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2 years ago

Are there equations with no horizontal asymptote

Mathematics

2 answers:

MrRa [10]2 years ago

8 0

Answer:

hbgjhbhv,h,gvh,v

Step-by-step explanation:

s2008m [1.1K]2 years ago

6 0

Answer:

The rational function f(x) = P(x) / Q(x) in lowest terms has no horizontal asymptotes if the degree of the numerator, P(x), is greater than the degree of denominator, Q(x)

Step-by-step explanation:

thank me later

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Choose the correct translation for the given statement.

Rainbow [258]

Answer: x > 10

Step-by-step explanation:

NOTE: exceed means "greater than"

x < 10 x is less than 10

x ≤ 10 x is less than or equal to 10

x > 10 x is greater than 10

x ≥ 10 x is greater than or equal to 10

8 0

2 years ago

Read 2 more answers

1. through (0,-1) slope= -1

nasty-shy [4]

Answer:

Step-by-step explanation:

I will give you equations in slope intercept form

y=-x-1

y= -2x - 6

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2 years ago

Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the same info

kow [346]

Graph is your answer look below for proof

have a good day!

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2 years ago

Bonjour j’ai un exercice de maths et je ne comprends rien

Minchanka [31]

Donc pour trouver la réduction de 30% nous allons trouver 30% de 49 alors nous allons faire 30 × 100 × 49 = 14,7 14,7 est la réduction maintenant nous devons faire 49 € -14,7 € soit 34,3 €, le prix est maintenant de 34,3 €, désolé d'utiliser Google Translate pour vous aider, mais j'espère que c'est correct :)

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2 years ago

The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)

Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores and D = difference between both

So, $\mu_A$ = Population mean for the math scores

$\mu_B$ = Population mean for the writing scores

Let $\mu_D$ = Difference between the population mean for the math scores and the population mean for the writing scores.

Null Hypothesis, $H_0$ : $\mu_A = \mu_B$ or $\mu_D$ = 0

Alternate Hypothesis, $H_1$ : $\mu_A \neq \mu_B$ or $\mu_D \neq$ 0

Hence, Test Statistics used here will be;

$\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ where, Dbar = Bbar - Abar

$s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$

n = 12

Student Math scores (A) Writing scores (B) D = B - A

1 540 474 -66

2 432 380 -52

3 528 463 -65

4 574 612 38

5 448 420 -28

6 502 526 24

7 480 430 -50

8 499 459 -40

9 610 615 5

10 572 541 -31

11 390 335 -55

12 593 613 20

Now Dbar = Bbar - Abar = 489 - 514 = -25

Bbar = $\frac{\sum B_i}{n}$ = $\frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}$ = 489

Abar = $\frac{\sum A_i}{n}$ = $\frac{540+432+528+574+448+502+480+499+610+572+390+593}{12}$ = 514

∑ $D_i^{2}$ = 22600 and $s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$ = $\sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} }$ = 37.05

So, Test statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$

= $\frac{-25 - 0}{\frac{37.05}{\sqrt{12} } }$ follows $t_1_1$ = -2.34

Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0

2 years ago