Compute the area <em>A</em> of ∆ABC.
• Take AB to be the base and CX (which is an altitude of ∆ABC) to be the height. Then the area is
<em>A</em> = 1/2 • AB • CX = 1/2 • 75 • CX
• Now take AC to be the base and BY (also an altitude) to be the height. Then
<em>A</em> = 1/2 • AC • BY = 1/2 • 70 • 60 = 2100
The areas must be equal, so we have
2100 = 1/2 • 75 • CX → CX = 4200/75 = 56
Answer:
The area of the shaded = 8 - 2π units²
Step-by-step explanation:
The area of the shaded portion = area square - area not shaded portion
Not shaded portion consists of two equal segments
∵ The side of the square = the radius of the circle = 2
∵ The measure of each angle of the square = π/2 (90° = π/2 rad)
∵ Area each segment = Area sector - area triangle
∵ Area triangle = 1/2 × (2) × (2) = 2 units²
∵ Area sector = (1/2)r²Ф ⇒ r = 2 , Ф = π/2
∴ Area sector = (1/2) (2)² (π/2) = π units²
∴ Area each segment = π - 2
∴ Area not shaded = 2(π - 2) = 2π - 4 units² ⇒ two segment
∵ Area square = 2 × 2 = 4 units²
∴ Area shaded portion = 4 - (2π - 4) = 4 - 2π + 4
= 8 - 2π units²
A integer that is divisible by 2 can be -2,-4,-6,4,2,6 or something else, but these are simpler.
Answer:
Step-by-step explanation:
The area of the pentagonal base, A = 33.5 cm²
The height of the prsim,h = 15 cm
We need to find the volume of the pentagonal base prism. The formula for the volume of the pentagonal base prism is given by :
So, the required volume is 
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