All categories

3 years ago

What is the answer to this 3/5 + (-1/5)=

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

6 0

Answer:

4/5

Step-by-step explanation:

3/5+1/5

3+1 /5

simplifies to:

4/5

You might be interested in

Leto [7]

Answer:

Options (B) and (C)

Step-by-step explanation:

Farmland owned by Dwight = 1600 acres

He wants to divide his farmland into four equal parts.

So the area of each part of the land will be = $\frac{\text{Area of the farmland}}{\text{Number of parts of the farmland}}$ = $\frac{1600}{4}$

This expression can be written in different ways,

$\frac{1600}{4}=$ 1600 ÷ 4

$=1600\times \frac{1}{4}$

Therefore, Options (B) and (C) will be the correct options.

4 0

3 years ago

Rate of change for y=1/3x

Marina86 [1]

Answer:

Rate of change or slope = $\frac{1}{3}$

Step-by-step explanation:

It is common that most lines that are graphed are in slope intercept form.

y=mx+b

M represents the slope.

In the question you're asking M = 1/3

3 0

3 years ago

Refer to the Venn diagram that represents the sports students chose to play at South High School last year. Select the correct d

vovikov84 [41]

I don't see a diagram, but if the portion of the tennis region you are asked to analyze doesn't intersect anywhere else/any other regions pertaining to other sports, wouldn't the sport chosen by these students be solely tennis?

8 0

3 years ago

Choose the point-slope form of the equation below that represents the line that

AfilCa [17]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Straight lines.

Since the slope of the line, m = -1/2

and we know that, line equation is, y=mx+c

so the answer is, option 1.)

1.) y-4 = -1/2 (x+6)

5 0

3 years ago

Right triangle XYZ has right angle Z. If the sin(X)=1213<br> , what is the cos(X)

AlekseyPX

Given:

Right triangle XYZ has right angle Z.

$\sin(x)=\dfrac{12}{13}$

To find:

The value of $\cos x$ .

Solution:

We know that,

$\sin^2(x)+\cos^2(x)=1$

$\cos^2(x)=1-\sin^2(x)$

$\cos(x)=\pm\sqrt{1-\sin^2x}$

For a triangle, all trigonometric ratios are positive. So,

$\cos(x)=\sqrt{1-\sin^2x}$

It is given that $\sin(x)=\dfrac{12}{13}$ . After substituting this value in the above equation, we get

$\cos(x)=\sqrt{1-(\dfrac{12}{13})^2}$

$\cos(x)=\sqrt{1-\dfrac{144}{169}}$

$\cos(x)=\sqrt{\dfrac{169-144}{169}}$

$\cos(x)=\sqrt{\dfrac{25}{169}}$

On further simplification, we get

$\cos(x)=\dfrac{\sqrt{25}}{\sqrt{169}}$

$\cos(x)=\dfrac{5}{13}$

Therefore, the required value is $\cos(x)=\dfrac{5}{13}$ .

6 0

3 years ago