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3 years ago

How do you solve this?

Mathematics

1 answer:

harina [27]3 years ago

7 0

Answer:

b. $\sqrt[3]{4x+2}$

Step-by-step explanation:

f(x) = ( x^3-2) /4

y = ( x^3-2) /4

Exchange x and y

x = ( y^3-2) /4

solve for y

Multiply each side by 4

4x = 4( y^3-2) /4

4x = y^3 -2

Add 2 to each side

4x+2 = y^3

Take the cubed root of each side

( 4x+2) ^ (1/3) = y^3 ^(1/3)

( 4x+2) ^ (1/3) =y

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The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio

zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0

3 years ago

Please help! Please?

yuradex [85]

1. x - y
2. xy
3. y / x
4. x+y
5. y= x-6
6. 6x =y
7. y-x
8. x/y
9. x+y= 6
10. xy= 6

3 0

3 years ago

Help me please fast

Natalija [7]

Answer:

Step-by-step explanation:

$\frac{5}{x-3}+\frac{2}{x+1}=3 \\\\\frac{5(x+1)+2(x-3)}{(x-3)(x+1)} =3\\\\5x+5+2x-6=3(x-3)(x+1)\\\\7x-1=3(x^2+x-3x-3)\\\\7x-1=3(x^2-2x-3)\\\\7x-1=3x^2-6x-9\\\\0=3x^2-6x-7x-9+1\\0=3x^2-13x-8$

Hence proved!

3 0

3 years ago

Help pls I need help pls answer quick

goldfiish [28.3K]

Answer:

Below.

Step-by-step explanation:

What we know: 4 Shaded. 12 in total.

That means,

12 divided by 4=3.

1/3 of the shape is shaded.

8 0

2 years ago

Part A is asking how long the bridge is and Part B is asking how expensive it would be if each foot it 1500

katrin [286]

Answer:

(a)80 feet

(b)$120,000

Step-by-step explanation:

Part A

Intersecting Secant-Tangent Theorem

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In the attached diagram, the theorem applied is:

$|AX|^2=|UX|*|TX|$

Comparing with our diagram:

|AX|=30 feet

|UX|=10 feet

Length of the Bridge,L

Therefore:

$30^2=10 X ($Length of the Bridge+10)$

900=10(L+10)

L+10=900/10

L+10=90

L=90-10=80 feet

Length of the Bridge=80 feet

Part B

If each foot costs $1500

Cost of the bridge=$1500*80=$120,000

4 0

3 years ago