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seropon [69]
3 years ago
8

Question 1

Mathematics
2 answers:
belka [17]3 years ago
8 0

Answer:

Yes I believe so

Step-by-step explanation:

sertanlavr [38]3 years ago
7 0
Is she is right because 2-1=1 and the equations is 2-1 3/8 so there will definitely be a fraction
You might be interested in
In parallelogram LMNO, what is the measure of angle N?<br><br> 50°<br> 70°<br> 110°<br> 130°
belka [17]

we know that

In a parallelogram opposite angles are congruent and consecutive angles are supplementary.

So

m∠O=m∠M

m∠L=m∠N

m∠O+m∠L=180

Step 1

Find the value of x

(x+20)+(2x+10)=180\\ 3x+30=180\\ 3x=180-30\\ x=\frac{150}{3} \\ \\ x=50\ degrees

Step 2

Find the value of angle L

m∠L=(2x+10)

m∠L=(2*50+10)

m∠L=110\ degrees

Remember that

m∠N=m∠L

m∠N=110\ degrees

therefore

the answer is

the measure of the angle N is equal to 110\ degrees





4 0
3 years ago
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Please help me last time I asked 2 days ago! No one answered. :(
pickupchik [31]

Answer: The answer is number 4

Step-by-step explanation:

5 0
3 years ago
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I’ll give you brainless please help me
Papessa [141]

Answer:

I'm pretty sure its 4

6 0
3 years ago
Use the distributive property to simplify the expression: -4(4x + 3) + (7x - 2)
Elodia [21]
-4(4x+3) + (7x -2) = (-16x + -12) + (7x + 2) = -16 + -12 + 7x + 2 = -9x -10
The answer is -9x -10
7 0
3 years ago
X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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