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timurjin [86]
3 years ago
11

0ω0 this is multiple choice i need help please 0ω0

Mathematics
2 answers:
NeX [460]3 years ago
8 0

(x,y) ---> (7,-3)

In a graph x is horizontal line while y is vertical line.

Right side of origin is positive x, while left side is negative.

Top of the origin is y positive while below the origin is negative.

Now the point: (7,-3)

x is 7

y is -3

So right 7 and 3 bottom

Answer: D

Naddik [55]3 years ago
3 0

Answer:

d) move 7 units right and 3 units down.

Step-by-step explanation:

From (0,0) which is the origin, move 7 units right. Right now it would be (7,y). Then move 3 units down which would be (7,-3)

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8 0
3 years ago
Easy Multiple Choice Questions about expressions and linear equations / ASAP / Will mark brainliest / 25 Points
nata0808 [166]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A

7.B

8.C

9.A

10. D

Step-by-step explanation:

For Problem 1, the work is as follows:

2(3x-1)+x\\Distribute\\6x-2+x\\7x-2

For Problem 2, the work is as follows:

(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5

For Problem 3, the work is as follows:

5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10

For Problem 4, the work is as follows:

4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1

For Problem 5, the work is as follows:

\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3

For Problem 6, the work is as follows:

17 *0.06 = 1.02\\17+1.02 = 18.02

For Problem 7, the work is as follows:

x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1

For Problem 8, the work is as follows:

y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1

For Problem 9, the work is as follows:

3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2

For Problem 10, the work is as follows:

(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5

Hope this Helps!

4 0
3 years ago
What is 9/16+1/2 equal to
Snowcat [4.5K]
17/16 is the answer since 1/2 is equal to 8/16. 8+9 is 17
4 0
4 years ago
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Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
jeka94

Let a,b,c be the time it takes for pumps A, B, and C (respectively) to fill 1 tank. Then

\begin{cases}\dfrac1a+\dfrac1b=\dfrac1{\frac65}=\dfrac56\\\\\dfrac1a+\dfrac1c=\dfrac1{\frac32}=\dfrac23\\\\\dfrac1b+\dfrac1c=\dfrac12\end{cases}

Now,

\left(\dfrac1a+\dfrac1b\right)-\left(\dfrac1a+\dfrac1c\right)=\dfrac56-\dfrac23\implies\dfrac1b-\dfrac1c=\dfrac16

Then

\left(\dfrac1b+\dfrac1c\right)+\left(\dfrac1b-\dfrac1c\right)=\dfrac12+\dfrac16\implies\dfrac2b=\dfrac23\implies b=3

This means

\dfrac1a+\dfrac13=\dfrac56\implies\dfrac1a=\dfrac12\implies a=2

and

\dfrac13+\dfrac1c=\dfrac12\implies\dfrac1c=\dfrac16\implies c=6

Working together, all 3 pumps would operate at a rate of

\dfrac1a+\dfrac1b+\dfrac1c=1

or 1 tank in 1 hour, so the answer is D.

8 0
3 years ago
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