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Svetach [21]
3 years ago
5

An art collage includes a red paper triangle with one side length of 3.4 inches and a second side length of 8.1 inches. Which of

the following could be the length of the third side?
a
15.3 inches

b
12.2 inches

c
6.8 inches

d
4.5 inches
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

D 4.5

..........................................

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Please help me with this and I need the work shown out please
givi [52]
Please note that you have to use the reason vert. opp. angles to find x, hope it helps:)

5 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
Graph: X^2+20-y^2-9x-4y+21-8x+6y-2=3-4y-5x-2y^2
Snezhnost [94]

Answer:

Step-by-step explanation:

8 0
3 years ago
A bus is travelling with 52 passengers. When it arrives at a stop, y passengers get off and 4 get on. At the next stop one-third
MissTica

52-y+4
(2/3) (52-y+4)+3=25 ;; (1/3) get off, so (2/3) left
(2/3)(52-y+4) =22
52-y+4=33
-y=-23
y=23
3 0
3 years ago
A fisherman can row upstream at 1 mph and downstream at 4 mph he started rowing upstream until he got tired and then rowed downs
Morgarella [4.7K]

Answer:the total trip, and I should be right, was 7 miles. He rowed up for 3 hours, and back for 1.

8 0
3 years ago
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