For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Your answer is ab -c
multiply both sides by B
Then subtract C
Answer: 5y
Step-by-step explanation:
Product means the multiplication of, so taking the product of 5 and y we simply have;
5*y=5y
G(-2) = 8 + 5(2)
= 8 - 10
= - 2
Since they are similar, that means they are proportionally the same.
So KL is similar to PN
JL is similar to PM
So,
You need to find how much bigger is the second triangle from first.
It is proportionally scaled up.
KL/JL = PN/ PM
You basically put in order of triangles. Left triangle on left side of equal sign and right triangle on right side of equal sign. You put in denominator the similar sides and numerator the similar sides (the side that is similar to the side of the other triangle)
5/6 = PN / 9
Cross-multiply
PN * 6 = 5*9
6PN = 45
PN =45/6
PN =7.5
