Answer:
#include <stdio.h>
typedef struct TimeHrMin_struct //struct
{
int hours;
int minutes;
} TimeHrMin;
struct TimeHrMin_struct SetTime(int hoursVal,int minutesVal) //SetTime function
{
struct TimeHrMin_struct str;
str.hours=hoursVal; //assigning the values
str.minutes=minutesVal;
return str; //returning the struct
}
int main(void)
{
TimeHrMin studentLateness;
int hours;
int minutes;
scanf("%d %d", &hours, &minutes);
studentLateness = SetTime(hours, minutes); //calling the function
printf("The student is %d hours and %d minutes late.\n", studentLateness.hours, studentLateness.minutes);
return 0;
}
Explanation:
Answer:
C. deriving benefits from highly focused and high technology markets
Explanation:
Firms that engage in cost-leadership approach seek to combine a low per-unit income with large sales for profit making purposes. Typically, but not always, they are more inclined to market their products and services to a large population base or a niche with a high demand volume. While differentiation enables a company to accomplish a competitive advantage. A Competitive advantage enables a company to achieve more strides over other companies offering related product substitutes. It is an important marketing process that is of critical economic importance to a business.
It should be noted that deriving benefits from highly focused and high technology markets is not part of the approaches to combining overall cost leadership and differentiation competitive advantages.
Answer:
A license that allows developers to change and share the source
code of the licensed software
Explanation:
i learned this, btw brainly stop removing my answers
Answer:
- import java.util.Scanner;
- public class num8 {
- public static void main(String[] args) {
- int first, second, third, fourth,total;
- double decimalOne, decimalTwo, decimalTotal;
- }
- public static void getData(int first, int second, int third, int fourth, double decimalOne, double decimalTwo){
- System.out.println("Enter the Values");
- Scanner in = new Scanner(System.in);
- first=in.nextInt();
- second=in.nextInt();
- third=in.nextInt();
- fourth=in.nextInt();
- decimalOne = in.nextDouble();
- decimalTwo = in.nextDouble();
- }
- public static int computeTotal(int first, int second, int third){
- return first+second+third;
- }
- public static int computeTotal(int first, int second, int third, int fourth){
- return first+second+third+fourth;
- }
- public static double computeTotal(double decimalOne, double decimalTwo){
- return decimalOne+decimalTwo;
- }
- public static void printAll( int first, int second, int third){
- System.out.println("Number one, two and three are: "+first+" "+second+" "+third);
- }
- public static void printAll( int first, int second, int third, int fourth){
- System.out.println("Number one, two and three and four are: "+first+" "+second+
- " "+third+" "+fourth);
- }
- public static void printAll( int first, int second, int third, int fourth, int fifth){
- System.out.println("Number one, two and three and four are: "+first+" "+second+
- " "+third+" "+fourth+" "+fifth);
- }
- public static void printAll( double first, double second, double third){
- System.out.println("Number one, two and three and four are: "+first+" "+second+
- " "+third);
- }
- }
Explanation:
This solution is provided in Java:
All the variable declarations are done in the main method (lines 3-6)
Eight methods as specified in the question are created (Lines 7, 17, 20, 23, 26, 29, 33 and 37).
Observe the concept of Method Overloading (i.e. methods with same name and return types but different parameter list)
