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2 years ago

Solve this equation for 15 points

Mathematics

1 answer:

Airida [17]2 years ago

4 0

Answer:

m=-7 is the answer to this equation

Step-by-step explanation:

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Hardy has three times as many tennis balls as kerns. They have 940 tennis balls in all. How many tennis balls does Hardy have th

topjm [15]

Answer:

Hardy has 470 more tennis balls than Kerns.

Step-by-step explanation:

Given that:

Total number of tennis balls = 940

Let,

x represents the number of tennis balls Hardy has.

y represents the number of tennis balls Kerns has.

According to given statement,

x+y=940 Eqn 1

x = 3y Eqn 2

Putting x = 3y in Eqn 1

3y+y=940

4y=940

Dividing both sides by 4

$\frac{4y}{4}=\frac{940}{4}\\y=235$

Putting y=235 in Eqn 2

x = 3(235)

x = 705

Difference = Hardy's tennis balls - Kerns' tennis balls

Difference = 705 - 235 = 470

Hence,

Hardy has 470 more tennis balls than Kerns.

3 0

3 years ago

I dont understand please help Which expression is equivalent to 8-(6r+2) A -6r+6 B 2r+2 C 6r+10 D -6r+10

Goryan [66]

Answer:

-6r+6

Step-by-step explanation:

Given data

We are given the expression

8-(6r+2)

let us expand it by opening the bracket

=8-6r-2

collect like terms

=8-2-6r

=6-6r

rearrange

=-6r+6

Hence option A is correct

8 0

2 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

8 0

2 years ago

What are the solutions to the quadratic equation 98-x2=0

kifflom [539]

$98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}$

8 0

3 years ago

The frequency table shows the results of drawing 20 cards from a bag of 100. There are an

zepelin [54]

Answer:

It's 50 percent right

Step-by-step explanation:

there are many colors and they could all be different

4 0

3 years ago