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Tasya [4]
3 years ago
9

Which number line represents the solution set for the inequality-1/2x>_4

Mathematics
1 answer:
Vesna [10]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Firstly, we solve for x

-x ≥ 2 * 4

-x ≥ 8

Multiply both sides by -1

x ≤ -8

So we look at the inequality represented by this;

We can see that the correct inequality is option B;

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5 a. 32% of 881
ira [324]

Answer:

Hope these helps

Step-by-step explanation:

5 a. 32% of 881 = 281.92

5 b. 39% of 719 = 280.41

6 a. 35% of 441 = 154.35

6 b. 67% of 429 = 287.43

7 a. 21% of 358 = 75.18

7 b. 47% of 6 =2.82

8 a. 67% of 811 = 543.37

8 b.

97% of 311 = 301.67

4 0
3 years ago
What is the y-intercept of the graph of the function f(x) = x2 + 3x + 5?
OLga [1]
Hello there!

How do you find the y-intercept?

Answer: To find the y-intercept, substitute in 0 for x and solve for y

y = x² + 3x + 5

y = (0)²  + 3(0) + 5

y = 0 + 0 + 5

y = 5

Thus, the correct answer is option D (0,5)

I really hope this answer is clear enough for you to understand. If you have questions about the answer, please let me know.

As always, I'm glad to be your helper this evening~!
3 0
2 years ago
Read 2 more answers
How would i approximate each irrational square root number to the nearest 0.05? 34, 82, 45, 104, -71, and -19
Digiron [165]

Using a calculator or a pencil, find each square root, including
three (3) decimal places.  A negative number has no real square
roots, so skip '-71' and '-19'.

For each square root . . .

-- If the digits in the 2nd and 3rd decimal place are 00 through 24, then
make the 2nd decimal place a '0' and discard the rest.

-- If the digits in the 2nd and 3rd decimal place are 25 through 74, then
make the 2nd decimal place a '5' and discard the rest.

-- If the digits in the 2nd and 3rd decimal place are 75 through 99, then
increase the 1st decimal place by 1, make the 2nd decimal place a '0',
and discard the rest.
4 0
3 years ago
What is the value of c such that the line y=2x+3 is tangent to the parabola y=cx^2
satela [25.4K]

The value of c such that the line y = 2\cdot x + 3 is tangent to the parabola y = c\cdot x^{2} is -\frac{1}{3}.

If y = 2\cdot x + 3 is a line <em>tangent</em> to the parabola y = c\cdot x^{2}, then we must observe the following condition, that is, the slope of the line is equal to the <em>first</em> derivative of the parabola:

2\cdot c \cdot x = 2 (1)

Then, we have the following system of equations:

y = 2\cdot x + 3 (1)

y = c\cdot x^{2} (2)

c\cdot x = 1 (3)

Whose solution is shown below:

By (3):

c =\frac{1}{x}

(3) in (2):

y = x (4)

(4) in (1):

y = -3

x = -3

c = -\frac{1}{3}

The value of c such that the line y = 2\cdot x + 3 is tangent to the parabola y = c\cdot x^{2} is -\frac{1}{3}.

We kindly invite to check this question on tangent lines: brainly.com/question/13424370

3 0
2 years ago
The graphs below have the same shape. What is the equation of the blue graph?
Radda [10]

Answer:

B

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift to the left of a units

• If a < 0 then a shift to the right of a units

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

g(x) is f(x) shifted 3 units right and 1 unit up , then

g(x) = (x - 3)² + 1 → B

3 0
2 years ago
Read 2 more answers
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