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monitta
3 years ago
8

ben used 124.7 pounds of gravel in his front yard 110.7 pounds in his back yard.how many more pounds of gravel does ben use in h

is front yard than his back yard
Mathematics
1 answer:
Dovator [93]3 years ago
6 0

Answer:

30.1

Step-by-step explanation:

it is subtraction because it is asking how many more pounds of gravel does Ben use in his front yard than his back yard and his front yard has a bigger number so you subtract.

136.2-106.1= 30.1

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How can i solve this<br> (x+2)(2x+3)<br> step by step please
MrRissso [65]

Answer:

2x² + 7x + 6

Step-by-step explanation:

To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).

You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.

(x+2)(2x+3)

2x²+ 3x + 4x + 6

2x² +7x + 6

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3 years ago
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Alla [95]

Answer:

She did not use the reciprocal of the divisor.

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How do you divide two fractions?
Ira Lisetskai [31]

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In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

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3 years ago
I need help can you plz help me
horrorfan [7]

Simplify

10/3

Convert to a mixed fraction

3 1/3

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3 years ago
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