Answer:who knows this
Step-by-step explanation:
Answer:
Step-by-step explanation:
I don't know if this is what you are looking for but, I would use substitution to solve what x and y are
6x+2y = 1
is the same as -6x-2y= -1 because if you multiply everything by -1 it will equal
6x+2y = 1
so now you have
6x+2y = 1
6x+2y = 1
I would set the equation equal to one variable and substitute.
6x+2y = 1 = 2y = 1 - 6x = y = (1/2) - (6x/2) = y = (1/2) - 3x
now plug in (1/2) - 3x in to one of the y's because they are the same equation
6x + (1/2) - 3x = 1
subtract 1/2
6x - 3x = 1/2
subtract the x's
3x = 1/2
now divide both sides by 3
x = (1/2)/ 3
x = 1/6
now that you know what x equals, plug that into the equation and find y
6(1/6) + 2y = 1
1 + 2y = 1
subtract 1
2y = 0
now divide to find y
y = 0/2
y = 0
so
x = 1/6 and y = 0
Hello!
This is a problem about probability.
What we would first do is find the theoretical probability that Susan would roll the number 3 on a die.
Assuming that this is a fair six sided die, there is only one face with the number 3, and there are 6 sides, meaning that the probability that Susan rolls a 3 would be
.
Now, Susan is rolling a die 1,086, meaning that we can divide this number by 6 to find the theoretical number of times that Susan would roll the number 3 on this die.
You should get 181 times, which would be a good estimate of how many times she could roll the number 3.
Hope this helps!
Answer:
Step-by-step explanation: