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Ugo [173]
3 years ago
9

Joe and Danny have just won 350 arcade tickets. If each arcade game can be played with 12 tickets, how many will they have left

over at the end of the day, if they play the maximum number of games?
Mathematics
2 answers:
lawyer [7]3 years ago
8 0

Answer:

2 tickets left

Step-by-step explanation:

12✖️29=348

350-348=2

maw [93]3 years ago
3 0

Answer:

If they play the maximum number of games, there will be two tickets left over.

Step-by-step explanation:

For this problem, I used long division.

350 divided by 12 comes out to be 29.

29 is the maximum number of games they could play.

29 times 12 is 348.

350 (the total number of tickets) minus 348 (number of tickets used) comes out to be two.

<em>Hope this helps! Brainliest would really help me out :)</em>

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A + c = 824                             represents number of tickets to sell
20a + 12c = 13,344                represents cost of each type of ticket

multiply equation 1 by -12 to cancel the variable 'c' and solve for 'a'

-12(a + c = 824)

-12a - 12c = - 9888
 20a + 12c = 13,344         add equations together
-----------------------------
    8a          = 3456           divide both sides by 8
     a = 432

To find children's tickets substitute adult numbers back into equation 1.
a + c = 824
432 + c = 824
subtract 432 from both sides
c = 392

adult 432, children 392
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