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Answer:
It can be concluded that participation in sports is dependent on grade level.
Step-by-step explanation:
In this case a Chi-square independence test for the data is to be performed at <em>α </em>= 0.01.
The hypothesis can be defined as follows:
H₀: The participation in sports is independent of grade level.
<em>Hₐ</em>: The participation in sports is dependent of grade level.
The data provided is:
Freshmen Sophomores Juniors Seniors
Yes 75 88 55 42
No 30 28 38 40
The formula to compute the expected frequencies is:
The Chi-square statistic is:
Consider the Excel file attached below.
The value of Chi-square statistic is 16.244.
The degrees of freedom of the test are:
Compute the <em>p</em>-value of the test as follows:
*Use a Chi-square table.
<em>p</em>-value = 0.001 < <em>α</em> = 0.01
The null hypothesis will be rejected at 1% level of significance.
Thus, it can be concluded that participation in sports is dependent on grade level.
Answer:
A. (2 × 6) + (3 × 8) + 6²
72 sq. inches.
B. 9 in. by 8 in.
Step-by-step explanation:
The white shape has dimensions of 2 in. by 6 in. and the green shape is a square.
So, the dimension of the green shape is 6 in. by 6 in.
Therefore, the length of the blue shape is (6 + 2) = 8 in.
Now, given that the area of the blue shape is 24 sq. in.
So, the width of the blue shape is in.
Now, if we consider the total figure, then area of the entire figure = area of the white shape + area of the green shape + area of the blue shape.
= (2 × 6) + (3 × 8) + 6² (Answer)
= 12 + 24 + 36
= 72 sq, inches. (Answer)
Now, the length of the entire figure is (6 + 3) = 9 in. and width of the entire figure is (2 + 6) = 8 in.
Therefore, the dimensions of the entire figure will be 9 in. by 8 in. (Answer)