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3 years ago

I am operations that undo each other like multiplication and divison

Mathematics

1 answer:

umka2103 [35]3 years ago

8 0

What's factoring 8 but not a multiple of 4. 8 and 4

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If f(x)=-3+7 and g(x)=-7+3, what is the value of f(-3) - g(3)

Andreyy89

F(x) = -3 + 7 = 4
g(x) = -7 + 3 = -4

f(-3) - g(3) = 4 - (-4) = 4 + 4 = 8

6 0

3 years ago

When in standard form, what is the value a, b, and c in this quadric 8x^2+3x-6=3x

borishaifa [10]

Answer:

a=8, b=0 and c=-6

Step-by-step explanation:

see pic for expln

8 0

2 years ago

Please helppppppppppppp

Klio2033 [76]

2+2+1 3/4+1 1/4+1+1=9 . Hope this helps :)

3 0

3 years ago

Read 2 more answers

Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours. Then pumps Y and Z started working an

madam [21]

Answer:

The correct option is B) 12.

Step-by-step explanation:

Consider the provided information.

Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours.

As we know: $rate =\dfrac{ work}{time}$ ,

The rate of pump X is $\frac{\frac{1}{4}}{2} = \frac{1}{8}$

$\frac{1}{4}$ of the water is pumped out of the tank, that means only $\frac{3}{4}$ is left to be pumped out.

All 3 pumps pumped out the remaining $\frac{3}{4}$ of the water out in 3 hours.

The combined rate of all three pumps is: $\frac{\frac{3}{4}}{3} = \frac{1}{4}$

Pump Y, working alone at its constant rate, would have taken 18 hours to pump out the rest of the water.

The rate of pump Y = $\frac{\frac{3}{4}}{18} = \frac{1}{24}$

Let z is the time taken by pump Z, then the rate of pump Z is $\frac{1}{z}$ .

Therefore,

$\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{z}=\dfrac{1}{4}$

Multiplying both sides by 24 z.

$3z + z + 24 = 6z\\24 = 2z\\12 = z$

Hence, the correct option is B) 12.

5 0

3 years ago

What is the transformation of f(x)= x^3:

mariarad [96]

Answer:

7. Down 5

8. Horizontal reflection

9. Vertical stretch by a factor of 5

Step-by-step explanation:

Transformations of Graphs (functions) is the process by which a function is moved or resized to produce a variation of the original (parent) function.

Transformations

For a > 0

$f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}$

$f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}$

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a$

$y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}$

$y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}$

$y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}$

Identify the transformations that take the parent function to the given function.

Question 7

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=x^3-5$

Comparing the parent function with the given function, we can see that 5 has been subtracted from the parent function.

Therefore, the transformation is:

$f(x)-5 \implies f(x) \: \textsf{translated}\:5\:\textsf{units down}$

Question 8

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=-x^3$

Comparing the parent function with the given function, we can see that the parent function has been multiplied by -1.

Therefore, the transformation is:

$y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}$

Question 9

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=5x^3$

Comparing the parent function with the given function, we can see that the parent function has been multiplied by 5.

Therefore, the transformation is:

$y=5\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:5$

Learn more about graph transformations here:

brainly.com/question/27845947

7 0

2 years ago

Read 2 more answers