The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
First step of a synthetic divison is that we need to carry down the leading coefficient. Here the leading coefficient is 2. So, carry down 2 at the bottom.
Next step is to multiply the divisor -3 with this carry down number 2. So, we have got 3*(-2)= -6 which will place atthe bottom of the next coefficient 4.
Next step is to add this column.
Now repeat the same method again till the last colum.
At the end we have got 0 after the addition. Which means the remainder is 0.
So, the quotient is 2x^2-2x+2.
√29/2 since cotangent deals the reciprocal of tangent and cotangent value is adjacent side/opposite side
Answer:
is A B and D
Step-by-step explanation: