Answer:
Step-by-step explanation:
Start with why C isn't the answer.
y = 1.8^0 . The power is zero. Anything to the zero power (anything except 0 to the 0 power) is 1. So 1.8^0 is 1 not something else. C assumes that somehow 0,1.8 turns into 1.8. It does not. The second part is also wrong but you don't need it. However here it is.
x = 0 y = 3
x = 1 y = 3 * 1.8 = 5.4
x = 2 y = 3 * 1.8^2 = 3*3.24 = 9.72
You should be able to see that if you multiply 5.4 by 3, you don't get 9.72
C just does not work.
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The actual answer is A. That's exactly what the graph does. If you multiply 5.4 * 1.8 you should get 9.72. Just for completeness, I've included the graph.
It would most likely be feet.
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
16.5?
Step-by-step explanation:
It's halfway between 16 and 17?
Answer:C
Step-by-step explanation:
78-17.5*2 = 43 so C
